Ask question

Ask question

All categories

3 years ago

13

HELL PICTURE SHOWN!!!

2 answers:

Arturiano [62]3 years ago

8 0

I believe it is A
Don't be mad at me if I get it wrong.
:-)

eduard3 years ago

6 0

Umm.... C? Maybe? I hope this is right?

You might be interested in

plzz help me no link plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz

boyakko [2]

Answer:

Zara ate 50 almonds last week

Step-by-step explanation:

part to whole ratio is 50 : 100

150 divided by 2 is 75

100 divided by 50 is equal to 2

Zara ate 50 almonds last week

pls mark brainliest if this helped :)

8 0

2 years ago

2 points) Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One

Stells [14]

$y'=(t+y)^2-1$

Substitute $u=t+y$ , so that $u'=y'$ , and

$u'=u^2-1$

which is separable as

$\dfrac{u'}{u^2-1}=1$

Integrate both sides with respect to $t$ . For the integral on the left, first split into partial fractions:

$\dfrac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)=1$

$\displaystyle\int\frac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)\,\mathrm dt=\int\mathrm dt$

$\dfrac12(\ln|u-1|-\ln|u+1|)=t+C$

Solve for $u$ :

$\dfrac12\ln\left|\dfrac{u-1}{u+1}\right|=t+C$

$\ln\left|1-\dfrac2{u+1}\right|=2t+C$

$1-\dfrac2{u+1}=e^{2t+C}=Ce^{2t}$

$\dfrac2{u+1}=1-Ce^{2t}$

$\dfrac{u+1}2=\dfrac1{1-Ce^{2t}}$

$u=\dfrac2{1-Ce^{2t}}-1$

Replace $u$ and solve for $y$ :

$t+y=\dfrac2{1-Ce^{2t}}-1$

$y=\dfrac2{1-Ce^{2t}}-1-t$

Now use the given initial condition to solve for $C$ :

$y(3)=4\implies4=\dfrac2{1-Ce^6}-1-3\implies C=\dfrac3{4e^6}$

so that the particular solution is

$y=\dfrac2{1-\frac34e^{2t-6}}-1-t=\boxed{\dfrac8{4-3e^{2t-6}}-1-t}$

3 0

3 years ago

I need help with this question please ASAP!!!!!!!!

Viefleur [7K]

For the one on the left they are corresponding and on the right they are vertical

4 0

3 years ago

Write an equation in slope-intercept form of the line that passes through (6, -1) and (3, 47)

katrin2010 [14]

Answer:

Step-by-step explanation:

(47+1)/(3-6) = 48/-3 = -16

y + 1 = -16(x - 6)

y + 1 = -16x + 96

y = -16x + 95

6 0

3 years ago

If g(x)= x^2-2x-6 and h(x)= 2x^2-5x+2 find (h-g) (-2)

Natalka [10]

Answer:

<h2> $(h - g)( - 2) = 18$ </h2>

Step-by-step explanation:

g(x) = x² - 2x - 6

h(x) = 2x² - 5x + 2

To find (h-g) (-2) we must first find h - g(x)

To find h - g(x) subtract g(x) from h(x)

We have

<h3> $(h - g)(x) = {2x}^{2} - 5x + 2 - ( {x}^{2} - 2x - 6) \\ = {2x}^{2} - 5x + 2 - {x}^{2} + 2x + 6 \\ = {2x}^{2} - {x}^{2} - 5x + 2x + 2 + 6$ </h3><h3> $(h - g)(x) = {x}^{2} - 3x + 8$ </h3>

To find (h-g) (-2) substitute the value of x that's - 2 into (h - g)(x) that's replace every x in (h - g)(x) by - 2

That's

<h3> $(h - g)( - 2) = ({ - 2})^{2} - 3( - 2) + 8 \\ = 4 + 6 + 8 \\ = 10 + 8$ </h3>

We have the final answer as

<h3> $(h - g)( - 2) = 18$ </h3>

Hope this helps you

7 0

3 years ago