Answer:
x=1,-5x=1,−5
Step-by-step explanation:
0=(x−1)(x+5)
2 Switch sides.
(x-1)(x+5)=0(x−1)(x+5)=0
3 Solve for xx.
x=1,-5x=1,−5
Answer:
12.7, because the absolute value gets rid of the negative integer, and shows it true value which is positive 12.7.
Step-by-step explanation: Have a Happy Thursday :)
Note that √(4 - t²) is defined only as long as 4 - t² ≥ 0, or -2 ≤ t ≤ 2. Then the real integral exists only if -2 ≤ x ≤ 2. (Otherwise we deal with complex numbers.)
If x = 2, then the integral corresponds to the area of a quarter-circle with radius 2. This means that the integral has a maximum value of 1/4 • π • 2² = π.
On the opposite end, if x = -2, then the integral has the same value, but the integral from 0 to -2 is equal to the negative integral from -2 to 0. So the minimum value is -π.
For all x in between, we observe that the integrand is continuous over the rest of its domain, so F(x) is continuous.
Then the range of F(x) is the interval [-π, π].
< 1 and < 2 are vertical angles...because they are opposite angles made by two intersecting lines
< 3 and < 4 are adjacent....because they have a common side and a common vertex
