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julia-pushkina [17]
3 years ago
6

The can is 12cm high and 8cm in diameter. Using formula V=TT r2h, how much is in the can

Mathematics
1 answer:
scoray [572]3 years ago
4 0
The formula you have given here is for the volume of a cylinder. It should read V =  \pi r^{2} h.
First, to find r, the radius, divide the diameter by two (since the radius is the distance from the circumference to the centre and the diameter is the distance from any point on the circumference to the opposite point (through the centre))

r = 8/2 = 4

Now we can calculate this.
V =  \pi *4^{2}*12 =  \pi * 16 * 12 = 603.185... \\ 
V = 603 cm^{3}

If your answer needs to be in litres, one cubic centimetre = one millilitre.

603 cm3 = 603mL = 0.603 L
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The lengths of a rectangle have been measured to the nearest tenth of a centimetre they are 87.3cm and 51.8cm what is the upper
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Answer: Area (upper bound) = 4527.7056 cm²

               Perimeter (lower bound) = 278 cm

<u>Step-by-step explanation:</u>

The length and width of the rectangle have been ROUNDED to the nearest tenth. Let's calculate what their actual measurements could be:

LENGTH: rounded to 87.3,  actual is between 87.25 and 87.34

<em>87.25 is the lowest number it could be that would round it UP to 87.3</em>

<em>87.34 is the highest number it could be that would round DOWN to 87.3</em>

WIDTH: rounded to 51.8, actual is between 51.75 and 51.84

<em>51.75 is the lowest number it could be that would round it UP to 51.8</em>

<em>51.84 is the highest number it could be that would round DOWN to 51.8</em>

To find the Area of the upper bound, multiply the highest possible length and the highest possible width:

A = 87.34 × 51.84 = 4527.7056

To find the Perimeter of the lower bound, calculate the perimeter using the lowest possible length and the lowest possible width:

P = 2(87.25 + 51.75) = 278

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