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koban [17]
2 years ago
12

During 2005, a company produced an average of 2,000 products per month. How many products will the company need to produce from

2006 through 2008 in order to increase its monthly average for the period from 2005 through 2008 by 200% over its 2005 average?
(A) 148,000
(B) 172,000
(C) 200,000
(D) 264,000
(E) 288,000
Mathematics
1 answer:
larisa86 [58]2 years ago
8 0

Answer:

264,000 (D)

Step-by-step explanation:

An average of 2000 products is produced per month.

In 2005, the company produced 2000*12 = 24000 products

The total amount of products produced between 2005 to 2008 if the company produces X products from 2006 to 2008 is

X + 24000

The average = (X + 24000)/4

The average is 200% higher than that in 2006

24000 + 200%(24000)

= 24000 + 48000

= 72,000

Therefore;

(X + 24000)/ 4= 72000

X + 24000 = 72000 * 4

X + 24000 = 288000

X = 288000 - 24000

X = 264000 (D)

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Height of the water increasing is at rate of  #(dh)/(dt)=3/(25 pi)m/(min)#

<h3>How to solve?</h3>

With related rates, we need a function to relate the 2 variables, in this case it is clearly volume and height. The formula is:

#V=pi r^2 h#

There is radius in the formula, but in this problem, radius is constant so it is not a variable. We can substitute the value in:

#V=pi (5m)^2 h#

Since the rate in this problem is time related, we need to implicitly differentiate wrt (with respect to) time:

#(dV)/(dt)=(25 m^2) pi (dh)/(dt)#

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So we need to substitute this in:

#(dh)/(dt)=(3m^3)/(min (25m^2) pi)=3/(25 pi)m/(min)#

Hence,  Height of the water increasing is at rate of  #(dh)/(dt)=3/(25 pi)m/(min)#

<h3>Formula used: </h3>

#V=pi r^2 h#

To Learn more visit:

brainly.com/question/4313883

#SPJ4

4 0
2 years ago
Read 2 more answers
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