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3 years ago

How does a foam-filled winter coat help keep a person warm?

1 answer:

andrey2020 [161]3 years ago

4 0

It slows down the transfer of thermal energy from outside to inside the coat. "NC"
It slows down the transfer of thermal energy from inside to outside the coat. 
It speeds up the transfer of thermal energy from outside to inside the coat. 
It speeds up the transfer of thermal energy from inside to outside the coat.

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An object displaces 652ml of water. What is the volume of the object

Eva8 [605]

If the object is completely submerged at that time, then the volume of
the full object is 652 cm³.

If only part of the object is in the water, then the volume of the part that's
in the water is 652 cm³, but we have no idea what its full volume is.

8 0

3 years ago

A tube 1.20 m long is closed at one end. A stretched wire is placed near the open end. The wire is 0.350 m long and has a mass o

Ksju [112]

Answer:

71.4583 Hz

67.9064 N

Explanation:

L = Length of tube = 1.2 m

l = Length of wire = 0.35 m

m = Mass of wire = 9.5 g

v = Speed of sound in air = 343 m/s

The fundamental frequency of the tube (closed at one end) is given by

$f=\frac{v}{4L}\\\Rightarrow f=\frac{343}{4\times 1.2}\\\Rightarrow f=71.4583\ Hz$

The fundamental frequency of the wire and tube is equal so he fundamental frequency of the wire is 71.4583 Hz

The linear density of the wire is

$\mu=\frac{m}{l}\\\Rightarrow \mu=\frac{9.5\times 10^{-3}}{0.35}\\\Rightarrow \mu=0.02714\ kg/m$

The fundamental frequency of the wire is given by

$f=\frac{1}{2l}\sqrt{\frac{T}{\mu}}\\\Rightarrow f^2=\frac{1}{4l^2}\frac{T}{\mu}\\\Rightarrow T=f^2\mu 4l^2\\\Rightarrow T=71.4583^2\times 0.02714\times 4\times 0.35^2\\\Rightarrow T=67.9064\ N$

The tension in the wire is 67.9064 N

7 0

3 years ago

Scientists use models to

xxTIMURxx [149]

D Is Thw Correct answer

3 0

4 years ago

A 10kg box is sliding at 50m/s. Find the momentum

MAXImum [283]

Answer:

The momentum of the ball is 500 kg·m/s

Explanation:

The momentum is given by Mass × Velocity

The given parameters are;

The mass of the box = 10 kg

The velocity by which the box is sliding = 50 m/s

Therefore, the momentum of the ball is given as follows;

The momentum of the ball = 10 kg × 50 m/s = 500 kg·m/s

The momentum of the ball = 500 kg·m/s

5 0

3 years ago

Anna is conducting an experiment to determine how weather affects cell phone reception. She is trying to decide the best way to

Anestetic [448]

Your answer should be D.
Hope this helps :)

5 0

3 years ago