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AlekseyPX
3 years ago
9

Anna is conducting an experiment to determine how weather affects cell phone reception. She is trying to decide the best way to

conduct her experiment in order to collect meaningful data.
Which of the following experiments would help Anna collect the best data?
A.
Test different cell phones in different locations on days with rainy weather.
B.
Test different cell phones in different locations on days with clear weather.
C.
Test a cell phone's reception in the exact same location under various atmospheric conditions.
D.
Test a cell phone's reception in one location with clear weather and in another location with rainy weather.
Physics
1 answer:
Anestetic [448]3 years ago
5 0
Your answer should be D.
Hope this helps :)
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A potential difference of 71 mV is developed across the ends of a 12.0-cm-long wire as it moves through a 0.27 T uniform magneti
Dafna1 [17]

Answer:

Explanation: please see attached file I attached the answer to your question.

7 0
3 years ago
10. Complete each of the following radioactive decay equations.
alukav5142 [94]

1. Alpha

Number next to Th is 231

(because 231 + 4 = 235)

The other number below the 4 is 2 - helium

(because 90 + 2 = 92)

2. Beta

Missing numbers are zero and one. Same as the one below it.

3. Beta

11 is the number above the C

(because 11 + 0 = 11)

5 is the number next to the B

(because 5 + 1 = 6)

Basically, the missing numbers must balance on both side of the equation; creating the elements you've started of with, meaning if you where to add the right side of the equation up - you should end up with the same protons and mass numbers you began with.

Hope this helps!

6 0
1 year ago
A uniform solid ball with a mass , M, is placed at the top of an inclined plane and released. What will be the velocity of the b
eimsori [14]

Answer:v=\sqrt{\frac{10}{7}\cdot gH}

Explanation:

Given

Mass of ball is M

Height of incline is H

Here conservation of energy will provide the velocity at bottom

Energy at top of incline plane =MgH

Energy at bottom=Kinetic energy+Rotational energy

Assuming Pure rolling we can write

v=\omega R

where v=velocity of ball

\omega=angular velocity of ball

R=radius of ball

E_b=\frac{1}{2}Mv^2+\frac{1}{2}I\omega ^2

where I=moment of inertia of ball

I=\frac{2}{5}MR^2

E_b=\frac{1}{2}Mv^2+\frac{1}{2}\times \frac{2}{5}MR^2\times (\frac{V}{R})^2

E_b=\frac{7}{10}Mv^2

Now ,

MgH=\frac{7}{10}Mv^2

v=\sqrt{\frac{10}{7}\cdot gH}

8 0
3 years ago
A particular atom becomes more energetically stable when it loses a single electron. It is most likely an atom of which of the f
Scorpion4ik [409]

Answer:

Magnesium (Mg)

Explanation:

because i checked

6 0
2 years ago
The sound intensity a distance d1 = 15.0 m from a chain saw is 0.260 W/m2. What is the sound intensity a distance d2 = 27.0 m fr
bagirrra123 [75]

Answer:

0.08024 W/m²

Explanation:

P = Power

d_1 = Distance = 15 m

I_1 = Intensity at 15 m = 0.26 W/m²

d_2 = Distance = 27 m

I_1 = Intensity at 27 m

Sound intensity is given by

I=\frac{P}{4\pi d^2}

\\\Rightarrow I\propto \frac{1}{d^2}

So, we have the relation

\frac{I_1}{I_2}=\frac{d_2^2}{d_1^2}\\\Rightarrow I_2=\frac{d_1^2\times I_1}{d_2^2}\\\Rightarrow I_2=\frac{15^2\times 0.26}{27^2}\\\Rightarrow I_2=0.08024\ W/m^2

The sound intensity at the given distance is 0.08024 W/m²

8 0
4 years ago
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