Answer:
, ,
Step-by-step explanation:
When you multiply like variables with each other, you add their powers together.
So...
1.
2.
3.
Answer:
x² - 9
Step-by-step explanation:
: Sum of the zeroes (α + β) = 0 and one zero (α) = 3 . On substituting β = - 3 in eq 1 . Hence, the required quadratic polynomial is x² - 9
166.66 try that i think it should be it
<span><span>y = 2 + 2sec(2x)
The upper part of the range will be when the secant has the smallest
positive value up to infinity.
The smallest positive value of the secant is 1
So the minimum of the upper part of the range of
y = 2 + 2sec(2x) is 2 + 2(1) = 2 + 2 = 4
So the upper part of the range is [4, )
The lower part of the range will be from negative infinity
up to when the secant has the largest negative value.
The largest negative value of the secant is -1
So the maximum of the lower part of the range of
y = 2 + 2sec(2x) is 2 + 2(-1) = 2 - 2 = 0
So the lower part of the range is (, 0].
Therefore the range is (, 0] U [4, )
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