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3 years ago

Write two fractions both not positive whose product is 5/8

Mathematics

1 answer:

dalvyx [7]3 years ago

3 0

Positive? So are these fractions negative? But here's my answer, 3/8 + 1/4 = 5/8.

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suppose that the probability of parents having a child with blond hair is 1/4.if there are 6 children in the family, what is the

Ahat [919]

Answer:

1.5 is the probablity

1/4×6

=1.5

hope it helps you

8 0

3 years ago

Hi, help with question 18 please. thanks

Vadim26 [7]

Answer:

See Below.

Step-by-step explanation:

We are given the equation:

$\displaystyle y^2 = 1 + \sin x$

And we want to prove that:

$\displaystyle 2y\frac{d^2y}{dx^2} + 2\left(\frac{dy}{dx}\right) ^2 + y^2 = 1$

Find the first derivative by taking the derivative of both sides with respect to <em>x: </em>

<em /> $\displaystyle 2y \frac{dy}{dx} = \cos x$ <em />

Divide both sides by 2<em>y: </em>

<h3><em /> $\displaystyle \frac{dy}{dx} = \frac{\cos x}{2y}$ <em /></h3>

<em />

Find the second derivative using the quotient rule:

$\displaystyle \begin{aligned} \frac{d^2y}{dx^2} &= \frac{(\cos x)'(2y) - (\cos x)(2y)'}{(2y)^2}\\ \\ &= \frac{-2y\sin x-2\cos x \dfrac{dy}{dx}}{4y^2} \\ \\ &= -\frac{y\sin x + \cos x\left(\dfrac{\cos x}{2y}\right)}{2y^2} \\ \\ &= -\frac{2y^2\sin x+\cos ^2 x}{4y^3}\end{aligned}$

Substitute:

$\displaystyle 2y\left(-\frac{2y^2\sin x+\cos ^2 x}{4y^3}\right) + 2\left(\frac{\cos x}{2y}\right)^2 +y^2 = 1$

Simplify:

$\displaystyle \frac{-2y^2\sin x-\cos ^2x}{2y^2} + \frac{\cos ^2 x}{2y^2} + y^2 = 1$

Combine fractions:

$\displaystyle \frac{\left(-2y^2\sin x -\cos^2 x\right)+\left(\cos ^2 x\right)}{2y^2} + y^2 = 1$

Simplify:

$\displaystyle \frac{-2y^2\sin x }{2y^2} + y^2 = 1$

Cancel:

$\displaystyle -\sin x + y^2 = 1$

Substitute:

$-\sin x + \left( 1 + \sin x\right) =1$

Simplify. Hence:

$1\stackrel{\checkmark}{=}1$

Q.E.D.

8 0

3 years ago

The sum of three number is 126. The third number is 4 times the second. The second number is 6 less than the first. What are the

joja [24]

Step-by-step explanation:

ASK

ALGEBRA II

Ingrid H.

asked • 04/02/20

The sum of three numbers is 126 . The third number is 3 times the first. The second number is 6 more than the first. What are the numbers?

The sum of three numbers is 126

. The third number is 3

times the first. The second number is 6

more than the first. What are the numbers?

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1 Expert Answer

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Mackenzie K. answered • 04/02/20

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Lets define a=1st number, b=2nd number, and c=3rd number

We know that a+b+c=126

We also know that the second number is 6 more than the first, so we can represent this as b=a+6

We also know that the third number is 3 times the first which can be represented as c=3a

We can plug these new values into our original equation and get:

a+(a+6)+(3a)=126

2a+6+3a=126 COMBINE LIKE TERMS

5a+6=126

5a=120

a=24

Our first number is 24.

Our second number is 6 more than our first number, so the second number is 24+6=30

Our third number is 3 times the first number, so the third number is 3(24)=72

We can check by plugging these numbers in for a, b, and c in our original equation

a+b+c=126

24+30=72=126

126=126

6 0

3 years ago

What two numbers add to -26 and multiply to -56

sweet [91]

Answer:

-28 and 2

Step-by-step explanation:

3 0

3 years ago

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Pls answer question 9 quickly I will mark as brainliest

kirza4 [7]

Answer:

80 degrees.

Step-by-step explanation:

THe reason why the 3 angles add up to 180 degrees is because they are the 3 angles in the triangle.

So m APB = 180 - 100

= 80 degrees.

4 0

3 years ago

Read 2 more answers