Find the area of a square with a side measure of 3x − 6 feet. Question 5 options: 9x2−36x+36 sq. ft. 9x2−6 sq. ft. 9x2+36x+36 sq
1 answer:
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Answer:
Step-by-step explanation:
Add 2 to both sides of the equation and divide both sides of the equation by 15. Then:
Apply base 8 to both sides of the equation:
Solve for "x", then you get:
<em>Note: your answer options suggest as if your actual question was</em>
<em>y = -4x - 9 instead of y = -x-9</em>
<em>But, anyways I am solving with respect to both equations </em>
Answer:
Please check the explanation.
Step-by-step explanation:
IN CASE YOUR EQUATION ⇒ y = -x - 9
The slope-intercept form of the line equation
y = mx+b
where m is the slope and b is the y-intercept
Given the line
comparing with the slope-intercept form (y = mx+b) of the line
- Therefore, slope of the line = m = -1
We know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line, such as:
slope = m = -1
perpendicular slope = – 1/m = -1/-1 = 1
Thus the slope of this perpendicular line will be: 1
IN CASE YOUR EQUATION ⇒ y = -4x - 9
Given the line
comparing with the slope-intercept form (y = mx+b) of the line
- Therefore, slope of the line = m = -4
We know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line, such as:
slope = m = -4
perpendicular slope = – 1/4 = -1/-4 = 4
Thus the slope of this perpendicular line will be: 4