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4 years ago

I need the answer for 90 please its due tommorow!

Mathematics

2 answers:

babunello [35]4 years ago

4 0

Jacqueline is incorrect.
To find how much trash you can clean in 4 days if you already know how much trash you can clean in one day, multiply 1 2/3 (how much you can clean in one day) by 4.
Another way to write 1 and 2/3 miles is 5/3 (converting a mixed number to a single fraction). Then, 5/3 x 4 = 20/3. (To multiply fractions, just multiply across, leaving 5 x 4 in the numerator and 4 x 1 in the denominator.)
Jacqueline said you would be able to clean 19/3 miles but you can actually clean 20/3.

abruzzese [7]4 years ago

4 0

Jacqueline is not correct. 12/3miles x 4 days = 5/3 x 4/1 = 20/3miles.

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You’re making deliveries and can travel 324 miles on 18 gallons of gas. How far can you travel on 41 gallons of gas?

sukhopar [10]

Answer:

738 miles

Step-by-step explanation:

324 miles = 18 gallons

18 miles = 1 gallon

738 miles = 41 gallons

4 0

3 years ago

Read 2 more answers

Solving right triangles

Sav [38]

<h2>1. Answer:</h2>

A right triangles is a triangle having a 90 degree side. According to the figure, the sides of this triangle are expressed in inches. Therefore, we can find the missing sides and angles as follows:

<u>m∠B:</u>

The sum of the three interior angles of any triangle is 180°, therefore:

$m \angle B + 51^{\circ} + 90^{\circ} = 180^{\circ} \\ \\ \boxed{m \angle B = 39^{\circ}}$

We must use the law of sines as follows:

$\frac{CA}{sin39^{\circ}}=\frac{9}{sin51^{\circ}} \\ \\ \therefore CA=\frac{9sin39^{\circ}}{sin51^{\circ}} \\ \\ \therefore \boxed{CA=7.3in}$

$\frac{AB}{sin90^{\circ}}=\frac{9}{sin51^{\circ}} \\ \\ \therefore AB=\frac{9sin90^{\circ}}{sin51^{\circ}} \\ \\ \therefore \boxed{AB=11.6in}$

<h2>2. Answer:</h2>

According to the figure, the sides of this triangle are expressed in meters. Therefore, we can find the missing sides and angles as follows:

<u>m∠A:</u>

The sum of the three interior angles of any triangle is 180°, therefore:

$m \angle A + 53^{\circ} + 90^{\circ} = 180^{\circ} \\ \\ \boxed{m \angle A = 37^{\circ}}$

We must use the law of sines as follows:

$\frac{CA}{sin53^{\circ}}=\frac{5}{sin90^{\circ}} \\ \\ \therefore CA=\frac{5sin53^{\circ}}{sin90^{\circ}} \\ \\ \therefore \boxed{CA=4.0m}$

$\frac{CB}{sin37^{\circ}}=\frac{5}{sin90^{\circ}} \\ \\ \therefore CB=\frac{5sin37^{\circ}}{sin90^{\circ}} \\ \\ \therefore \boxed{CB=3.0m}$

<h2>3. Answer:</h2>

According to the figure, the sides of this triangle are expressed in miles. Therefore, we can find the missing sides and angles as follows:

<u>m∠B:</u>

The sum of the three interior angles of any triangle is 180°, therefore:

$m \angle A + 28^{\circ} + 90^{\circ} = 180^{\circ} \\ \\ \boxed{m \angle B = 62^{\circ}}$

We must use the law of sines as follows:

$\frac{CB}{sin28^{\circ}}=\frac{29.3}{sin62^{\circ}} \\ \\ \therefore CB=\frac{29.3sin28^{\circ}}{sin62^{\circ}} \\ \\ \therefore \boxed{CA=15.6mi}$

$\frac{AB}{sin90^{\circ}}=\frac{29.3}{sin62^{\circ}} \\ \\ \therefore AB=\frac{29.3sin90^{\circ}}{sin62^{\circ}} \\ \\ \therefore \boxed{AB=33.2mi}$

<h2>4. Answer:</h2>

According to the figure, the sides of this triangle are expressed in miles. Therefore, we can find the missing sides and angles as follows:

<u>m∠A:</u>

The sum of the three interior angles of any triangle is 180°, therefore:

$m \angle A + 24^{\circ} + 90^{\circ} = 180^{\circ} \\ \\ \boxed{m \angle A = 66^{\circ}}$

We must use the law of sines as follows:

$\frac{CA}{sin66^{\circ}}=\frac{14}{sin90^{\circ}} \\ \\ \therefore CA=\frac{14sin66^{\circ}}{sin90^{\circ}} \\ \\ \therefore \boxed{CA=12.8mi}$

$\frac{CB}{sin24^{\circ}}=\frac{14}{sin90^{\circ}} \\ \\ \therefore CB=\frac{14sin24^{\circ}}{sin90^{\circ}} \\ \\ \therefore \boxed{CB=5.7mi}$

8 0

3 years ago

A toy rocket is fired into the air from the top of a barn. It's height h in yards above the ground after t seconds is given by t

mariarad [96]

Answer:

The rocket reached its maximum height at 2 seconds.

The maximum height of the rocket is 36 yards.

Step-by-step explanation:

Quadratic equation:

In the format

$h(t) = ah^{2} + bh + c$

The maximum height happens at the instant of time:

$t_{v} = -\frac{b}{2a}$

The maximu height is $h(t_{v})$

In this question:

$H(t) = -3t^{2} + 12t + 24$

So $a = -3, b = 12, c = 24$

When did the rocket reach its maximum height?

$t_{v} = -\frac{12}{2*(-3)} = 2$

The rocket reached its maximum height at 2 seconds.

What was the maximum height of the rocket?

H(2).

$H(2) = -3*2^{2} + 12*2 + 24 = 36$

The maximum height of the rocket is 36 yards.

3 0

3 years ago

10. Find the value of x in the equation 2(x - 3) + 5x = 5(2x + 6).

RoseWind [281]

Option A

<u>Answer: </u>

The value of x in the equation 2(x - 3) + 5x = 5(2x + 6) is -12

<u>Solution: </u>

From question given that

2(x - 3) + 5x = 5(2x + 6)

Open the brackets,

2x – 6 + 5x = 10x + 30

Rewrite the above equation,

2x + 5x – 6 = 10x + 30

On simplifying the above equation, we get

7x – 6 = 10x + 30

Now adding 6 on both sides,

7x – 6 + 6 =10x + 30 + 6

7x = 10x + 36

On subtracting 10x on both sides,

7x - 10x = 10x + 36 - 10x

-3x = 36

On dividing -3 on both sides,

x = -12

Hence on simplifying 2(x - 3) + 5x = 5(2x + 6) we get value of x is -12. Hence Option (A) is correct.

7 0

4 years ago

Use the the image below to determine the angle type, relationship, value of x, and the missing angle measures.

Alexeev081 [22]

Answer:

Name: alternate exterior angles

Relationship: they are congruent. (15x + 5)° = (14x + 11)

Value of x: 6

Missing angle measures: 95°

6 0

3 years ago