Answer:
The probability of finding a sample mean less than 18 hours is 0.0082
Step-by-step explanation:
To find the probability of finding a sample mean less than 18 hours, we need to calculate the z-score of this sample mean 18. And the probability of finding a sample mean less than 18 hours is P(z<z(18)).
Z-score can be calculated as follows:
z(18)=
where
- X is the sample mean (18 hours)
- M is the average hours dentists spend per week on fillings (20 hours)
- s is the standard deviation (10 hours)
- N is the sample size (144)
Putting the numbers, we get:
z(18)=
Using z- table we can find that P(z<z(18)) = 0.0082
Answer:
1.08 × 10^11
Step-by-step explanation:
Subtract: (1.8*10^11)-(7.2*10^10)
Answer:
Roughly speaking, in a normal distribution, a score that is 1 s.d. above the mean is equivalent to the 84th percentile. ... In other words, roughly 95 percent of students are within two standard deviations – positive or negative – of the average
<span>468 3/4 divided by 6 1/4 = 75 sections</span>
<h3>
<u>Explanation</u></h3>
f(a) means the value of f(x) is ... when x = a. That means if we substitute x = 3, we would get f(3).
f(3) also means the value of f(x) is ... when x = 3.
f(x) can also be defined as y // f(x) = y
You can find the value of f(x) at specific domain from the graph by looking at x = 3 then look up to where the point or where the graph passes. From the graph, when x = 3 as we look up and the graph passes y-coordinate at 1.
Therefore we can say that when x = 3, y = 1.
<h3>
<u>Answer</u></h3>
f(3) = 1
