The given equation is 
where h is the height, in feet, of a ball and t is the time, in seconds.
<u>Part a: The height of the ball when t = 2 seconds:</u>
The height of the ball above the ground 2 seconds after it is released can be determined by substituting t= 2 in the equation , we get;
Simplifying the terms, we get;
Thus, the height of the ball after 2 seconds is 100 feet.
<u>Part b: The height of the ball when t = 4 seconds:</u>
The height of the ball above the ground 4 seconds after it is released can be determined by substituting t = 4 in the equation , we get;
Simplifying the terms, we get;
Thus, the height of the ball after 4 seconds is 68 feet.
Answer:
25% of 50000 is 12500
Step-by-step explanation:
To find: 25% of 50000
solution:
25% = 
hence, 25% of 50000 = 
50000
= 12500
Therefore, the answer is 12500.
Simplify the following:
(6^5/7^3)^2
7^3 = 7×7^2:
(6^5/(7×7^2))^2
7^2 = 49:
(6^5/(7×49))^2
7×49 = 343:
(6^5/343)^2
6^5 = 6×6^4 = 6 (6^2)^2:
((6 (6^2)^2)/343)^2
6^2 = 36:
((6×36^2)/343)^2
| | 3 | 6
× | | 3 | 6
| 2 | 1 | 6
1 | 0 | 8 | 0
1 | 2 | 9 | 6:
((6×1296)/343)^2
6×1296 = 7776:
(7776/343)^2
(7776/343)^2 = 7776^2/343^2:
7776^2/343^2
| | | | 7 | 7 | 7 | 6
× | | | | 7 | 7 | 7 | 6
| | | 4 | 6 | 6 | 5 | 6
| | 5 | 4 | 4 | 3 | 2 | 0
| 5 | 4 | 4 | 3 | 2 | 0 | 0
5 | 4 | 4 | 3 | 2 | 0 | 0 | 0
6 | 0 | 4 | 6 | 6 | 1 | 7 | 6:
60466176/343^2
| | | 3 | 4 | 3
× | | | 3 | 4 | 3
| | 1 | 0 | 2 | 9
| 1 | 3 | 7 | 2 | 0
1 | 0 | 2 | 9 | 0 | 0
1 | 1 | 7 | 6 | 4 | 9:
Answer: 60466176/117649
Answer:
(-3,2)
Step-by-step explanation:
Eliminate the equal sides of each equation and combine
5x + 17 = -2x - 4
Solve
x = -3
Evaluate y when x = −
3
.
y = 2
(-3,2)
<em>hope this helps :)</em>
