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Naya [18.7K]
2 years ago
8

What is this i HATE math Oh MY GOD

Mathematics
2 answers:
Leviafan [203]2 years ago
8 0

Answer:

i hate math toooo but the answer is 1/16

Step-by-step explanation:

Ann [662]2 years ago
3 0
As a Decimal it is 0.0625
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A right triangle has legs of 5 ft and 6 ft. What is the length of the hypotenuse? _____ ft.
yarga [219]

Answer:

2.) 7.8

Step-by-step explanation:

We can use Pythagorean theorem

a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse

5^2 + 6^2 = c^2

25+36 = c^2

61 = c^2

Take the square root of each side

sqrt(61) = sqrt(c^2)

7.810249676 = c

7 0
3 years ago
Read 2 more answers
The graph below shows the distance a car can
Gnom [1K]

Answer:

yyyyyyyyyy

Step-by-step explanation:

yyyyyyyyyyyyyyy

5 0
2 years ago
The number of visitors to a state park in one year was greater than 62,558 but less than 62,808. Which could have been the numbe
AnnyKZ [126]

Answer:250

Step-by-step explanation:

6 0
3 years ago
If there was a total of 30 computers and the computer lab is removing 3 broken computers and adding 13 wireless devices, about w
Liula [17]

32.5 % of lab are wireless devices

<em><u>Solution:</u></em>

Given that there was a total of 30 computers and the computer lab is removing 3 broken computers and adding 13 wireless devices

Now we can first find out total number of computers and devices in lab

total number of computers and devices in lab = 30 computers - 3 + 13 wireless devices

total number of computers and devices in lab = 30 - 3 + 13 = 40

So there are 40 computers and wireless devices in lab

<em><u>To find: what percent of the lab are wireless devices</u></em>

So we have to find what percent of 40 is 13

Let "a" be the required percent

a % of 40 = 13

\frac{a}{100} \times 40 = 13\\\\a = \frac{13 \times 100}{40}\\\\a = 32.5

32.5 % of of lab are wireless devices

6 0
3 years ago
Hi I'm the mom I would like to see if you can help me with this problem
Tanya [424]

From the statement of the problem, we know that:

• a train starts at City A and travels 2,158 km to City B,

,

• then it travels 3,793 km from City B to City C.

The distance between City A and City C is equal to the sum of the distance from City A to City B, and the distance from City B to City C. So the distance between City A and City C is 2,158 km + 3,793 km = 5951 km.

Looking at the answer of Clay:

<em>2,158 + 3,793 = (2,158 + 7) + (3,793 + 7) = 2,165 + 3,800 = 5,965</em>

We see that he added 7 km to each of the distances, that's the reason why he found a different a wrong result.

5 0
1 year ago
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