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valkas [14]
3 years ago
6

At one time, the Texas Junior College Teachers Association annual conference was held in Austin. At that time a taxi ride in Aus

tin was $1.15 for the first 1/5 of a mile and $0.35 for each additional 1/5 of a mile. If the distance from one of the convention hotels to the airport is 8.5 miles, how much will it cost to take at taxi from that hotel to the airport? (Round your answer to the nearest cent.)
Mathematics
1 answer:
slavikrds [6]3 years ago
5 0
$6.75 would be your answer.
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What will be 66 2/3 as a percent explanation
VashaNatasha [74]
66.666666 repeated decimal
You would keep the 66 as is, and divide 2 by 3. That equals 0.66666666666 repeated, so the answer would be 66.666666 (rounded: 66.67)
6 0
4 years ago
The expression 7z-9p+9z-z
nika2105 [10]

Answer:

15z - 9p

Step-by-step explanation:

7z - 9p + 9z - z

=7z - 9p +8z

= -9p + 15z or 15z - 9p Answer

Hope this helps!

4 0
4 years ago
Can someone answer this
MA_775_DIABLO [31]

Answer:

10 inches

Step-by-step explanation:

18*2=36

56-36=20

20/2= 10

The missing side length is 10 inches.

Hope this helps! Have a nice day :)

5 0
3 years ago
Read 2 more answers
Land in downtown Columbia is valued at $10 a square foot. What is the value of a triangular lot with sides of lengths 119, 147,
stiks02 [169]

Answer:

$87,461

Step-by-step explanation:

Given that the dimensions or sides of lengths of the triangle are 119, 147, and 190 ft

where S is the semi perimeter of the triangle, that is, s = (a + b + c)/2.

S = (119 + 147 + 190) / 2 = 456/ 2 = 228

Using Heron's formula which gives the area in terms of the three sides of the triangle

= √s(s – a)(s – b)(s – c)

Therefore we have = √228 (228 - 119)(228 - 147)(228 - 190)

=> √228 (109)(81)(38)

= √228(335502)

=√76494456

= 8746.1109071 * $10

= 87461.109071

≈$87,461

Hence, the value of a triangular lot with sides of lengths 119, 147, and 190 ft is $87,461.

6 0
3 years ago
Which statement explains how the lines 2x + y = 4 and y = one halfx + 4 are related?
KatRina [158]

Answer:

They are perpendicular

Step-by-step explanation:

To solve this problem .

we will convert the equations in slope intercept form.

Slope intercept  form of equation is y = mx+c

where m is slope of line and c is y intercept.

________________________________

equation 1 is

2x+y = 4

=> y =4 - 2x or y = -2x + 4

comparing it with y = mx + c

m = -2  , c = 4

_________________________________________

equation 2 is y = one halfx + 4 ( one half is same as 1/2)

so equation is

y = x/2 +4

comparing it with y = mx + c

m = 1/2  , c = 4

_________________________________________

Now lets evaluate options

They are parallel.  wrong option

For lines to be parallel slope should be same.

But here slope are different -2 and 1/2 .

Thus lines are not parallel.

__________________________________________

They are perpendicular.  correct option

For lines to be perpendicular, product of slope should be equal to -1.

-2*1/2 = -1

we can see that product of slope should be equal to -1 .

Thus lines are  perpendicular

______________________________________

They are the same line.  wrong option

For lines to be same both slope and y intercept should  be same.

Y intercept is same but the slopes are different -2 and 1/2  .

Thus lines are not  the same line.

__________________________________________

They are not related.       wrong option

As we have found that the lines are perpendicular .

So this option is intuitively wrong

4 0
3 years ago
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