The value of y in the triangle is 6°.
<h3>How to calculate the value of y in the triangle?</h3>
Firstly, it's important to note that a triangle has the total angles of 180°.
Based on the information, the triangle has interior angle measures of 11y, 10y + 10°, and 10y - 16º.
The value of y in the triangle will be illustrated thus:
11y + 10y + 10 + 10y - 16 = 180
31y - 6 = 180
31y = 180 + 6.
31y = 186
Divide.
y = 186 / 31
y = 6
The value of y is 6.
Learn more about triangles on:
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Answer:
<em>The answers are for option (a) 0.2070 (b)0.3798 (c) 0.3938
</em>
Step-by-step explanation:
<em>Given:</em>
<em>Here Section 1 students = 20
</em>
<em>
Section 2 students = 30
</em>
<em>
Here there are 15 graded exam papers.
</em>
<em>
(a )Here Pr(10 are from second section) = ²⁰C₅ * ³⁰C₁₀/⁵⁰C₁₅= 0.2070
</em>
<em>
(b) Here if x is the number of students copies of section 2 out of 15 exam papers.
</em>
<em> here the distribution is hyper-geometric one, where N = 50, K = 30 ; n = 15
</em>
<em>Then,
</em>
<em>
Pr( x ≥ 10 ; 15; 30 ; 50) = 0.3798
</em>
<em>
(c) Here we have to find that at least 10 are from the same section that means if x ≥ 10 (at least 10 from section B) or x ≤ 5 (at least 10 from section 1)
</em>
<em>
so,
</em>
<em>
Pr(at least 10 of these are from the same section) = Pr(x ≤ 5 or x ≥ 10 ; 15 ; 30 ; 50) = Pr(x ≤ 5 ; 15 ; 30 ; 50) + Pr(x ≥ 10 ; 15 ; 30 ; 50) = 0.0140 + 0.3798 = 0.3938
</em>
<em>
Note : Here the given distribution is Hyper-geometric distribution
</em>
<em>
where f(x) = kCₓ)(N-K)C(n-x)/ NCK in that way all these above values can be calculated.</em>
3√24= 3√2^2*6 = 3*2√6 = 6√6
2√384= 2√8^2*6 = 2*8√6 = 16√6
√96= √4^2*6 = 4√6
6√6 -16√6- 4√6 = -14√6
Final answer: -14√6
Answer:
240:60 is equvilent to 15:15
