Since the two equations equal y, set them equal to each other.
x-1=-2x+5
From there, solve for x.
First get x on one side, by using the addition property of equality.
x-1=-2x+5
3x-1=5
Isolate x by adding 1.
3x=6
Lastly get x all by itself by dividing each side by 3.
x=2
You can now substitute your x-value, 2, into one of the equations (or both, if you wish; either one will result in the same answer.)
y=x-1
y=2-1
y=1
OR
y=-2x+5
y=-2(2)+5
y=-4+5
y=1
Final answer:
x=2 and y=1
Any questions or anything you would like me to clarify, feel free to ask :)
Tan 34 = 12/x and then uhm, put 12/tan34 into ur calculator
Answer: v-(kx8)
Step-by-step explanation: plz mark me brainliest
Answer:
J=12
Step-by-step explanation:
(2/3)*j = 8 // - 8
(2/3)*j-8 = 0
2/3*j-8 = 0 // + 8
2/3*j = 8 // : 2/3
j = 8/2/3
j = 12
Answer:
The figure is attached and the total distance is 1031 feet.
Step-by-step explanation:
The graph is indicated in the attached figure.
For calculation of distance consider following
Point Flagpole is (0,0)
Point Clue1 is (0,5)
Point Clue2 is (6,0)
Point Clue3 is (0,-5)
So the distance is calculated as follows
![d_{T}=[d_{FP\ to\ Clue1}+d_{Clue1\ to\ Clue2}+d_{Clue2\ to\ Clue3}]*distance\ per\ unit\\d_{T}=[\sqrt{(Clue1_x-FP_x)^2+(Clue1_y-FP_y)^2}+\sqrt{(Clue2_x-Clue1_x)^2+(Clue2_y-Clue1_y)^2}+\sqrt{(Clue3_x-Clue2_x)^2+(Clue3_y-Clue2_y)^2}]**distance\ per\ unit\\](https://tex.z-dn.net/?f=d_%7BT%7D%3D%5Bd_%7BFP%5C%20to%5C%20Clue1%7D%2Bd_%7BClue1%5C%20to%5C%20Clue2%7D%2Bd_%7BClue2%5C%20to%5C%20Clue3%7D%5D%2Adistance%5C%20per%5C%20unit%5C%5Cd_%7BT%7D%3D%5B%5Csqrt%7B%28Clue1_x-FP_x%29%5E2%2B%28Clue1_y-FP_y%29%5E2%7D%2B%5Csqrt%7B%28Clue2_x-Clue1_x%29%5E2%2B%28Clue2_y-Clue1_y%29%5E2%7D%2B%5Csqrt%7B%28Clue3_x-Clue2_x%29%5E2%2B%28Clue3_y-Clue2_y%29%5E2%7D%5D%2A%2Adistance%5C%20per%5C%20unit%5C%5C)
Substituting the values
![d_{T}=[\sqrt{(0-0)^2+(5-0)^2}+\sqrt{(6-0)^2+(0-5)^2}+\sqrt{(0-6)^2+(-5-0)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{(0)^2+(5)^2}+\sqrt{(6)^2+(-5)^2}+\sqrt{(-6)^2+(-5)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{0+25}+\sqrt{36+25}+\sqrt{36+25}]*50 \text{ feet}\\d_{T}=[\sqrt{25}+\sqrt{61}+\sqrt{61}]*50 \text{ feet}\\d_{T}=[5+7.81+7.81]*50 \text{ feet}\\d_{T}=[20.62]*50 \text{ feet}\\d_{T}=1031 \text{ feet}\\](https://tex.z-dn.net/?f=d_%7BT%7D%3D%5B%5Csqrt%7B%280-0%29%5E2%2B%285-0%29%5E2%7D%2B%5Csqrt%7B%286-0%29%5E2%2B%280-5%29%5E2%7D%2B%5Csqrt%7B%280-6%29%5E2%2B%28-5-0%29%5E2%7D%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B%5Csqrt%7B%280%29%5E2%2B%285%29%5E2%7D%2B%5Csqrt%7B%286%29%5E2%2B%28-5%29%5E2%7D%2B%5Csqrt%7B%28-6%29%5E2%2B%28-5%29%5E2%7D%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B%5Csqrt%7B0%2B25%7D%2B%5Csqrt%7B36%2B25%7D%2B%5Csqrt%7B36%2B25%7D%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B%5Csqrt%7B25%7D%2B%5Csqrt%7B61%7D%2B%5Csqrt%7B61%7D%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B5%2B7.81%2B7.81%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B20.62%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D1031%20%5Ctext%7B%20feet%7D%5C%5C)
So the total distance travelled is 1031 feet.
