Divide 2y from all terms
2y(y^2+6y+9)
Let the lengths of pregnancies be X
X follows normal distribution with mean 268 and standard deviation 15 days
z=(X-269)/15
a. P(X>308)
z=(308-269)/15=2.6
thus:
P(X>308)=P(z>2.6)
=1-0.995
=0.005
b] Given that if the length of pregnancy is in lowest is 44%, then the baby is premature. We need to find the length that separates the premature babies from those who are not premature.
P(X<x)=0.44
P(Z<z)=0.44
z=-0.15
thus the value of x will be found as follows:
-0.05=(x-269)/15
-0.05(15)=x-269
-0.75=x-269
x=-0.75+269
x=268.78
The length that separates premature babies from those who are not premature is 268.78 days
$28,000
X 48%
-----------
$13,440
The truck would be worth $13,440 by the end of the 3 year time span. Hope this helps!
Answer:
Yes they are equivalent because if you divide 18 by 6 it is 3 and if you do the same for 21 and 7 it also equals 3 which means they get paid 3 per hour
As for 6 they are not bec if we do the same from to 6 220/25=8.8 and 90/10=9 meaning they don’t have the same feet to inches
Step-by-step explanation:
I hope this helps and I’m not to late.
