Answer:
Number of monthly calls = 475
Step-by-step explanation:
Given:
Plan 1 = $30 per month unlimited calls
Plan 2 = $11 + $0.04(per call)
Find:
Number of monthly calls, plan 1 better than plan 2
Computation:
Plan 1 (Cost) < Plan 2 (Cost)
30 < 11 + 0.04(x)
19 < 0.04(x)
475 < (x)
Number of monthly calls = 475
Answer:
0.6495
Step-by-step explanation:
This is question based on conditional probability
The probability that a customer plans to make a purchase = 0.32.
The probability that a customer plans not to make a purchase = 1 - 0.32
= 0.68
The probability of responding to an advertisement given that the customer plans to make a purchase = 0.63
The probability of responding to an advertisement given that a person does not plan to make a purchase = 0.16.
Given that a person responds to the advertisement, what is the probability that they plan to make a purchase is calculated as:
0.32 × 0.63/(0.32 × 0.63) + (0.16 × 0.68)
= 0.2016/ 0.2016 + 0.1088
= 0.2016/0.3104
= 0.6494845361
Approximately = 0.6495
Answer:
There is 2 apples
Step-by-step explanation:
(9^x) - 3 = 2*3^x
(9^x) - 3 - (2*3^x) = (2*3^x) - (2*3^x)
(9^x) - (2*3^x) - 3 = 0
(3^2)^x - 2*(3^x) - 3 = 0
3^(2x) - 2*(3^x) - 3 = 0
3^(x*2) - 2*(3^x) - 3 = 0
(3^x)^2 - 2*(3^x) - 3 = 0
z^2 - 2*z - 3 = 0 ............ let z = 3^x
(z - 3)(z + 1) = 0
If z-3 = 0, then z = 3 when we isolate z
If z = 3, and z = 3^x, then
z = 3
3^x = 3
3^x = 3^1
x = 1
which is a solutin in terms of x
If z+1 = 0 then z = -1
If z = -1 and z = 3^x, then there are NO solutions for this part of the equation
The quantity 3^x is never negative no matter what the x value is
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Answer: x = 1
