3 years ago

Evaluate the expression 5(9-4)^2-3^2

1 answer:

Kay [80]3 years ago

3 0

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andrey2020 [161]

9514 1404 393

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32.8 m/s

Step-by-step explanation:

The function is actually ...

$v(d) = \sqrt{2gd}$

Filling in the given values, the velocity is about ...

$v(55) = \sqrt{2\cdot9.8\cdot55}=\sqrt{1078}\approx32.8\text{ m/s}$

The velocity at the end of the free-fall is about 32.8 meters per second.

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Licemer1 [7]

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malfutka [58]

$\frac{2x^3y^3}{4y^2} = \frac{x^3y^3}{2y^2} = \frac{x^3y}{2}$

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Gnoma [55]

Makes the value a negative

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2 years ago