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Allisa [31]
3 years ago
12

Maya has 28 apples, 12 oranges, and 8 mangos. She wants to put an equal number of each kind of fruit into baskets so all of the

baskets will be the same. What is the greatest number of fruit that can be put in each basket?
Mathematics
2 answers:
Amiraneli [1.4K]3 years ago
8 0

We are given that Maya has 28 apples, 12 oranges, and 8 mangoes.

Now she wants to put equal number of each type of fruits in each basket.

So we have to find the greatest common factor of 28 , 12 and 8.

Factors of 28 are : 1, 2, 4, 7, 14 and 28

Factors of 12 are : 1, 2, 3, 4, 6, 12

Factors of 8 are: 1, 2, 4 and 8

So here GCF of 28, 12 and 8 is 4.

Answer: So she can put 4 Apples, 4 Oranges and 4 mangoes in each basket.

marysya [2.9K]3 years ago
4 0
12 in each basket.

28÷4= 7
12÷4= 3
8÷4=2
7+3+2= 12

Hope this helps!
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Hi student, let me help you out! :)

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

We are asked to find the two integers, given that they are consecutive, and their sum is 65.

\triangle~\fbox{\bf{KEY:}}

  • Consecutive integers are right next to each other, like 12 and 13. or 65 and 66.

Let the first integer be x, and let the second integer be x+1.

Their sum is 65. Let's set up our equation:

\longmapsto\sf{x+x+1=65}

Combine like terms:

\longmapsto\sf{2x+1=65}

Subtract 1 from both sides of the equal sign:

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Divide both sides by 2:

\longmapsto\sf{x=32}

To find the second integer, subtract the first integer from the sum of the two integers:

\longmapsto\pmb{65-32}

\longmapsto\pmb{33}

The integers are: 33 and 32.

Hope it helps you out! :D

Ask in comments if any queries arise.

#StudyWithBrainly

~Just a smiley person helping fellow students :)

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