Help asap please!! 50 points and BRAINLIEST!!! Thank you!!

Mathematics

1 answer:

netineya [11]3 years ago

4 0

Answer:

Like radicals are radicals that have the same number in the radical sign

So it would be 3√7 and 11√7 (reasoning is they both have a 7 underneath the radical sign)

For the second one Simplify: 35√11-√11

you want to subtract like normal 35√11-1√11, (since there isn't a number there we are going to put one)

35-1=34

34√11, You want to keep the √11, because it is like having like terms but instead of variables it is √

34√11

The third one: Simplify: 15√6+3√6

we want to do the same thing as the problem above so,

15+3=18

18√6, again you want to keep the radical the same

18√6

For the fourth one: 5√7+√7-2√7

you want to do one step at a time so

5√7+√7= 6√7 (again you would have a one in front of the √7, then you would keep your radicals the same)

Then you want to subtract that to your other one

6√7-2√7= 4√7

6-2=4, (again keep the radical the same)

4√7

For the last one

3√5*√10+11√5*√10-√5

You always want to multiply first as in PEMDAS

Lets take this one step at a time also

First 3√5*√10

When multiplying radicals you would multiply like normal

3√50 (√5*√10= √50)

3√50

Now lets do 11√5*√10

again √5*√10=√50

so 11√50

Now you are going to add your two answers together

3√50+11√50= 14√50 (you would add 3+11=14, keep the radicals the same)

Don't forget about your -√5

14√50-√5, this as simplified as you can get so your answer is

14√50-√5

I hope this helps you ;)

Step-by-step explanation:

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madreJ [45]

You plot the point of the focus and the directrix on the graph to determine where the parabola opens.
We are provided the general forms of parabola according to its opening if:
it opens upward: (x - h)² = 4a(y - k)
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where "h" and "k" are the coordinates of the vertex, and "a" is the focal length from the focus to the vertex.

As you plot, the directrix y = 9 is a horizontal line, and the focus at (0,-9) is below that directrix. So, it means that the parabola opens downward (and not upward because the parabola must not touch to the directrix). Next, identity the vertex (h,k). Note that the vertex is the midpoint between the focus and the point of the directrix. So the vertex is (0,0). Then, the focal length "a" is 9.
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