18 1/4 pieces she will have now
:)
Answer:
I can't see the question
Step-by-step explanation:
sorry
maybe try asking the same question again
SOLUTION
The mean is 4min
standard deviation is 1min
the z score is

where

then we have

The probability the call lasted less than 3 min will be
Therefore, the probability that (z < -1 ) is
[tex]\begin{gathered} Pr(z<-1)=Pr(0
Hence, the percentage of the calls that lasted less than 3 min is 16%
Answer:
Answer to your query is provided below in the image attached
Answer:
1/6
Step-by-step explanation:
gradient= change in y/ change in x
-4--5/2--4= 1/6
1/6 is the gradient