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TiliK225 [7]
3 years ago
12

A. 5/8 B. -8/5 C. 8/5 D. -5/8

Mathematics
1 answer:
Alexus [3.1K]3 years ago
4 0

Answer:

A

Step-by-step explanation:

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6.Jerome scored a 88% on the last quiz. If there were 100 questions, how many did he answer correctly?​
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Jerome answered 88 questions correctly

Step-by-step explanation:

88% is the equivalent of 88 questions out of 100 in this scenario, also meaning he answered 12%, or 12 questions wrong.

5 0
3 years ago
−3+5+6g=11−3g solve for g
bixtya [17]
-3+5+6g=11-3g
6g+3g= 11+3-5
9g = 9
g=9/9=1
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how much are the tickets and refreshments?

Step-by-step explanation:

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42.92

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3 0
3 years ago
Consider a drug testing company that provides a test for marijuana usage. Among 317 tested​ subjects, results from 25 subjects w
svet-max [94.6K]

Answer:

We conclude that we fail to reject H_0 as there is not sufficient evidence to warrant support of the claim that less than 10 percent of the test results are wrong.

Step-by-step explanation:

We are given that among 317 tested​ subjects, results from 25 subjects were wrong.

We have to test the claim that less than 10 percent of the test results are wrong.

<u><em>Let p = proportion of subjects that were wrong.</em></u>

So, Null Hypothesis, H_0 : p = 10%     {means that 10 percent of the test results are wrong}

Alternate Hypothesis, H_A : p < 10%     {means that less than 10 percent of the test results are wrong}

The test statistics that would be used here <u>One-sample z proportion</u> <u>statistics</u>;

                      T.S. =  \frac{\hat p-p}{\sqrt{\frac{\hat p (1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of test results that were wrong = \frac{25}{317} = 0.08

           n = sample of tested subjects = 317

So, <u><em>test statistics</em></u>  =  \frac{0.08-0.10}{\sqrt{\frac{0.08 (1-0.08)}{317} } }

                              =  -1.31

The value of z test statistics is -1.31.

Now, the P-value of the test statistics is given by the following formula;

                P-value = P(Z < -1.31) = 1 - P(Z \leq 1.31)

                              = 1 - 0.9049 = <u>0.095</u>

<u><em>Now, at 0.05 significance level the z table gives critical value of -1.645 for left-tailed test.</em></u><em> Since our test statistics is more than the critical value of z as -1.31 > -1.645, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which </em><em><u>we fail to reject our null hypothesis</u></em><em>.</em>

Therefore, we conclude that we fail to reject H_0 as there is not sufficient evidence to warrant support of the claim that less than 10 percent of the test results are wrong.

5 0
3 years ago
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