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3 years ago

4k – 3 = -2k + 3 help me please lol

Mathematics

2 answers:

hoa [83]3 years ago

6 0

Answer: k=1

Step-by-step explanation:

4k-3=-2k+3

take -3 and 3 and add them up on one side and change the sign

4k=-2k+3

4k=-2k+6

take the -2k and change the sign and add to 4k

4k=6

6k=6

now divide both sides with x

6k/6= 6/6

k= 1

Sophie [7]3 years ago

3 0

I hope this helps :)

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3 years ago

AM is a median in △ABC (M∈ BC ). A line drawn through point M intersects AB at its midpoint P. Find areas of △APC and △PMC, if A

Snowcat [4.5K]

Answer:

The area of APC is 70m². The area of triangle PMC is 35m².

Step-by-step explanation:

Let the area of triangle ABC be x.

It is given that AM is median, it means AM divides the area of triangle in two equal parts.

$\text{Area of }\triangle ACM=\text{Area of }\triangle ABM=\frac{x}{2}$ .....(1)

The point P is the midpoint of AB, therefore the area of APC and BPC are equal.

$\text{Area of }\triangle APC=\text{Area of }\triangle BPC=\frac{x}{2}$ ......(2)

The point P is midpoint of AB therefore the line PM divide the area of triangle ABM in two equal parts. The area of triangle APM and BPM are equal.

$\text{Area of }\triangle APM=\text{Area of }\triangle BPM=\frac{x}{4}$ .....(3)

The area of triangle APM is 35m².

$\text{Area of }\triangle APM=\frac{x}{4}$

$35=\frac{x}{4}$

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Therefore the area of triangle ABC is 140m².

Using equation (2).

$\text{Area of }\triangle APC=\frac{x}{2}$

$\text{Area of }\triangle APC=\frac{140}{2}$

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Therefore the area of triangle APC is 70m².

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3 years ago

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4 years ago

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