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Nadya [2.5K]
3 years ago
9

ALGEBRA 1 HONORS QUESTION:

Mathematics
2 answers:
WITCHER [35]3 years ago
8 0
The cost function that represents this scenario:
move for a flat fee $1.50 plus an additional $1.25 for each night.
the additional fee for each night represent x.
the equation should be: 

a. c(x) = 1.50 + 1.25x

hope this help

IrinaVladis [17]3 years ago
4 0
The correct answer is A!
c(x) = 1.50 + 1.25x

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Mike sold H hats. Nate sold three times as many hats as Mike. Write an expression for the number of hats Nate sold.​
Lubov Fominskaja [6]

Answer:

3 times Mike's amount = 3h

4 0
2 years ago
28 students in the class 75% pass how many students pass
SashulF [63]

Answer:

21 students pass

Step-by-step explanation:

Firstly, you can set up the problem into an equation where the variable X would equal the number of students passing. You put X over the total number of students in the class, turning it into a fraction, then set it equal to the fraction  \frac{75}{100} (which is 75% represented as a fraction).

\frac{X}{28} = \frac{75}{100}

The fraction \frac{75}{100} can be simplified, because 75 and 100 are both multiples of 25, so after canceling out the 25s you would be left with \frac{3}{4}.

\frac{X}{28} = \frac{3}{4}

Next, you use the process of cross multiplication which is essentially just multiplying the denominators of both fractions (which would be 28 and 4 in this case) to each side of the equation.

\frac{X}{28} * 28 * 4 = \frac{3}{4} * 4 * 28

The denominators cancel out leaving you with a simple equation to simplify.

4* X =  3 * 28

4X = 84

Finally, divide both sides by four in order to isolate the variable.

\frac{4X}{4} = \frac{84}{4}

X = 21.

5 0
3 years ago
Can someone actually help me please?
Tamiku [17]
D and B is the anwser
5 0
2 years ago
Simplify the following expression.<br><br> 0.466 × 1.2
Ganezh [65]

Answer:

0.466 \times 1.2 \\  \frac{699}{1250}   \:  \: or \:  \: 0.55

6 0
2 years ago
Read 2 more answers
Find the area between the two functions
Inga [223]

The area between the two functions is 0

<h3>How to determine the area?</h3>

The functions are given as:

f₁(x)= 1

f₂(x) = |x - 2|

x ∈ [0, 4]

The area between the functions is

A = ∫[f₂(x) - f₁(x) ] dx

The above integral becomes

A = ∫|x - 2| - 1 dx (0 to 4)

When the above is integrated, we have:

A = [(|x - 2|(x - 2))/2 - x] (0 to 4)

Expand the above integral

A = [(|4 - 2|(4 - 2))/2 - 4] - [(|0 - 2|(0 - 2))/2 - 0]

This gives

A = [2 - 4] - [-2- 0]

Evaluate the expression

A = 0

Hence, the area between the two functions is 0

Read more about areas at:

brainly.com/question/14115342

#SPJ1

5 0
1 year ago
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