Please, see the offered decision:
1) common equation for lines is y=kx+b. If k₁=k₂ (for line 1 and line 2) ⇒ 'line 1' || 'line 2'.
2) for line 3x+5y=6 k= -3/5. It means (according to item 1) for unknown line k is the same (-3/5).
3) using points (0;3) it is easy to find parameter b (x=0, y=3) via y=kx+b:
3=0*(-3/5)+b ⇔ b=3.
4) finaly (k=-3/5; b=3):
Answer:
2x^2 is not equivalent
Step-by-step explanation:
3x = 3x
2x^2 = 2x^2
X(2+1) = 3x
2x + x = 3x
the odd one out is 2x^2
Given:
A prism with right triangular base.
Base of triangle = 6 ft
Height of triangle = 8 ft
Height of prism = 7
To find:
The volume of the given prism.
Solution:
The volume of prism is:
...(i)
Where, B is the base area and h is the height of the prism.
In the given figure, the base of the prism is a right angle triangle with legs 6 ft and 8 ft. So, the area of the base is:
Substituting 
in (i), we get
Therefore, the volume of the prism is 168 cubic ft.
Answer:
y-3x
Step-by-step explanation:
Because it is subtracted from y that meas the y would be first and 3 times x would be 3x because you do not need a sign because it is a variable
Answer:
A≅407.34 au (area units)
Step-by-step explanation:
we must find the area generated by equations a., b., and c. To do this we must graph and the areas and determine their points to evaluate
As seen in the graphs (1, 2) we have the area generated by equations a. b. and the limits within which the area should be evaluated are those determined by c.
Finally we find A (view graph 3)
