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Nezavi [6.7K]
3 years ago
6

Which factorization is equivalent to 4y2 − 17y + 15? A) (y − 3)(4y + 5) B) (y + 3)(4y − 5) C) (y − 3)(4y − 5) D) (4y − 3)(y − 5)

Mathematics
1 answer:
Delicious77 [7]3 years ago
6 0
The answer to this is (4y - 5)(y - 3)
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Solution is K = -7

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given the weekly demand curve of a local wine producer is p= 50-0.1q, and that the total cost function is c= 1500+ 10q, where q
ipn [44]

Answer:

a)the weekly profit as a function of price isP=-10 p^2 + 600 p - 6500

b) a bottle of wine be sold at $30 to realise maximum profit

c) the maximum profit that can be made by the producer is $2500

Step-by-step explanation:

The weekly demand curve of a local wine producer is p= 50-0.1q

p = price

q = quantity

Revenue function R =Price \times Quantity

R=(50-0.1q)q

R=50q-0.1q^2

Cost function: c= 1500+ 10q

Profit function=R(x)-C(x)

Profit function= 50q-0.1q^2-1500-10q

Profit function= 40q-0.1q^2-1500   ----1

We have q = 500 - 10 p using p = 50 − 0.1q

P=-0.1 (500 - 10 p)^2 + 40 (500 - 10 p)- 1500\\P= -10 p^2 + 600 p - 6500

General quadratic equation:ax^2+bx+c=0

On comparing

a = -0.1 , b = 40 , c = -1500

Maximum Profit is at q = \frac{-b}{2a}=\frac{-40}{2(-0.1)}=200

To find price must a bottle of wine be sold to realise maximum profit

p= 50-0.1q

p= 50-0.1(200)=30

Substitute the value of q in profit function(1) get the maximum profit

So, Profit function= 40\left(200\right)-0.1\left(200\right)^{2}-1500=2500

Hence

a)the weekly profit as a function of price isP=-10 p^2 + 600 p - 6500

b) a bottle of wine be sold at $30 to realise maximum profit

c) the maximum profit that can be made by the producer is $2500

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3 years ago
Square root of 0.7056
aniked [119]

Answer:

.84

Step-by-step explanation:

√ .7056 put in calculator

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A runner burned 120 calories on a 1.6 km run. How many calories would they burn on a 5 km run
labwork [276]
1) Let's first find how many calories a runner burns on 1 km: R=120/1.6= 75 (calories/km)
2) On 5 km he will burn: Calories=5*R=5*75= 375 (calories)
______
375 calories he would burn on 5 km.
5 0
4 years ago
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