Answer:
P(C4) = 0.0711
Step-by-step explanation:
consider the first draw = 15/23 since it cannot be a blue ball
The second draw = 21/29 since 6 more red balls will be added after the draw since a blue ball cannot be drawn
the third draw = 27/35 since 6 more red balls will be added after each draw since a blue ball cannot be drawn
therefore the total number of red balls will be = 15 + 6 + 6 + 6 = 33 red balls after the 4th draw. the total ball now in the urn= 33 red + 4 blue = 41
Hence the probability of drawing a blue ball at the fourth draw after drawing red balls at the previous attempts = 8/41
P(C4) = P ( fourth ball is blue ) * P( first ball red)*P(second ball red) *P(third ball red )
= (8/41) * (15/23) * (21/29)* (27/35) = 0.0711
Answer:
There is a discontinuity at x=1
Step-by-step explanation:
Answer:
B.) 36/60
Step-by-step explanation:
some
equivalent fractions of 9/15:
3/5 = 6/10 = 9/15 = 12/20 = 15/25 = 18/30 = 21/35 = 24/40 = 27/45 = 30/50 = 33/55 = 36/60
Answer:
The consecutive even numbers are 28, 30, 32, 34
Step-by-step explanation:
let the four consecutive even numbers be: b d f h,
such that:
b=b, d=b+2, f=b+4, h=b+6.
Therefore, 2(b+b+2)=3(b+6)+14
b=28,
d=(b+2)=30
f=(b+4)=32
h=(b+6)=34
B, because the mid segment is half the length of the third side