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ololo11 [35]
3 years ago
9

Hi can someone help please​

Mathematics
2 answers:
Art [367]3 years ago
7 0

Answer:

Step-by-step explanation:

1. PQR is an equilateral triangle formed by 3 diagonals of the cube. Therefore, it would be 60 degrees. 2. An angle which measures less than 90° is called an acute angle. The measure between 0° to 90°. In the picture below, the angle formed by the intersection of PQ and QR at Q forms an angle PQR which measures 45°. Thus, PQR is called an acute angle.

ankoles [38]3 years ago
5 0

Answer:

put ur protactor from the middle to where its up to then look at where the line is and you will get your answer

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posledela

Answer:

what is this question?

Step-by-step explanation:

7 0
3 years ago
Please help me with this Math question...
kati45 [8]

Answer:

A) length = 9cm, width = 4 cm

Step-by-step explanation:

The key word "times" refers to multiplication, so if you're trying to find dimensions at 1/4 times its original size, you need to multiply the original dimensions by 1/4.

l = 36

new l = 36 (1/4)

          = 36/4

          = 9 cm

w = 16

new w = 16 (1/4)

            = 16/4

            = 4 cm

5 0
3 years ago
Problem page the ratio of men to women working for a company is 5 to 8 . if there are 169 employees total, how many women work f
Ksenya-84 [330]
5 : 8....added = 13

5/13(169) = 845/13 = 65 men
8/13(169) = 1352/13 = 104 women <===
8 0
3 years ago
Given sin theta= 6/11 and sec theta &lt; 0, find cos theta and tan theta.
bekas [8.4K]

Answer: option a.

Step-by-step explanation:

By definition, we know that:

cos^2(\theta)=1-sen^2(\theta)\\\\tan(\theta)=\frac{sin(\theta)}{cos(\theta)}

Substitute sin(\theta)=\frac{6}{11} into the first equation, solve for the cosine and simplify. Then, you obtain:

cos(\theta)=\±\sqrt{1-(\frac{6}{11})^2}\\\\cos(\theta)=\±\sqrt{\frac{85}{121}}\\\\ cos(\theta)=\±\frac{\sqrt{85}}{11}

As sec\theta then cos\theta:

cos(\theta)=-\frac{\sqrt{85}}{11}

Now we can find tan\theta:

tan\theta=\frac{\frac{6}{11}}{-\frac{\sqrt{85}}{11}}\\\\tan\theta=-\frac{6\sqrt{85}}{85}

4 0
3 years ago
Read 2 more answers
What is the algebraic rule?? And how do you find out what algebraic rule on a graph is (x,y)to (x,y+10)??? I know how to find ba
Arlecino [84]

Answer:

  (x, y) ⇒ (-x, y)

Step-by-step explanation:

When you're looking for a rule that transforms one figure to the other, the first step is to look at the figures. You want to identify their orientation (order of vertices) and the relative locations of corresponding vertices.

Here, vertices VWX are in <em>clockwise</em> order. The corresponding vertices V'W'X' are in <em>counterclockwise</em> order. For that to happen, there must be a reflection involved.

The y-axis goes through the midpoints of VV', WW' and XX'. This means the y-axis is the line of reflection. The coordinates of V'W'X' have the same y-values as their originals, but their x-values have changed sign.

The algebraic rule for these two figures is ...

  (x, y) ⇒ (-x, y) . . . . . . reflection over y-axis; sign of x changes

__

<em>Additional comment</em>

No rotation is involved here.

The rule (x, y) ⇒ (x, y+10) means the y-coordinate has had 10 added to it. That causes a translation upward by 10 units. This <em>is</em> the algebraic rule.

7 0
1 year ago
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