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Arada [10]
3 years ago
14

Rachel Plant has ​$28,000 invested in stock A and stock B. Stock A currently sells for ​$20 a share and stock B sells for ​$80 a

share. If stock B doubles in value and stock A goes up​ 50%, her stock will be worth ​$54,000. How many shares of each stock does she ​own?
Mathematics
1 answer:
Wewaii [24]3 years ago
3 0

Answer:

A= 66.6667

B = 333.3333

Step-by-step explanation:

Initial value of A = $20

Initial value of B = $80

Initial total=$ 28000

A moves up 50%= 20+(0.5*20)

A moves up 50% = 20+10

A moves up 50% =$ 30

B double it values = $80*2

B double it values = $160

Now total value is = $54000

A20+B80= 28000... equation 1

A30+B160= 54000.... equation 2

Multiplying equation 1 * 2

Multiplying equation 2 * 1

A40 +B160 = 56000

A30+B160= 54000

A30 = 2000

A= 2000/30

A= 200/3

A= 66.6667

A20+B80= 28000

Substituting A

200/3 (20) +B80= 28000

B80= 28000-4000/3

B80= 80000/3

B= 80000/240

B = 333.3333

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3 years ago
Please solve the following question.
mylen [45]

Answer:

103, 776

Step-by-step explanation:

There are 48 possibilities, and you are picking 3.

Now, the order does matter (aka, if the same 3 athletes won but got different places, we would still consider it to be a separate possibility)

(this is considered "without repetitions")

the number of permutations (arrangement combinations where the order does matter) without repetitions formula:

Number of permutations

without <em>repetitions </em>= nPr

= \frac{n!}{(n-r)!}

(

[the P is for combinations [where the order does matter, if the order didn't matter then it would be C, and it would be a different formula.]

n is the total number of objects.

r is the number of objects selected]

<em>(a repetition would be like two versions of the same person competing, which doesn't make sense)</em>

{the ! means factorial:

5! = 5 x 4 x 3 x 2 x 1}

{for example, if there are 5 people to give a presentation, and they can go in any order [but cannot repeat their presentation], so they all must fill 5 slots}

{for the first slot there are 5 choices, the second slot there are 4 choices...}

)

So, if we follow this formula:

\frac{n!}{(n-r)!}

n: 48

r: 3

\frac{48!}{(48-3)!}

= \frac{48!}{45!}

=\frac{48 * 47*46*45!}{45!}

(the 45! cancel out)

= 48 * 47 * 46

= 103, 776

(or, without the formula:

for the first choice (lets say of gold), there are 48 options

for the second choice (lets say silver), there are 47 options left to choose from

for the third choice (lets say bronze), there are 46 options left to choose from

)

3 0
2 years ago
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