Answer:
110°
Step-by-step explanation:
mFG = 2×<FEG = 2×55 = 110°
Answered by GAUTHMATH
To the nearest foot, it would be 23 feet. I found this using the Pythagorean Theorem of a (squared) + b (squared) = c (squared). If you have 24 as the hypotenuse, you have to square this and subtract 64 (8*8) from it. That will equal 512. So you have to find the square root of that which is 22.62, which will round to 23 feet.
Answer:
36 feet.
Step-by-step explanation:
We have been given that a ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is
. We are asked to find the maximum height of the ball.
We can see that our given equation is a downward opening parabola, so its maximum height will be the vertex of the parabola.
To find the maximum height of the ball, we need to find y-coordinate of vertex of parabola.
Let us find x-coordinate of parabola using formula
.



So, the x-coordinate of the parabola is
. Now, we will substitute
in our given equation to find y-coordinate of parabola.






Therefore, the maximum height of the ball is 36 feet.
Answer: C
Step-by-step explanation:
the normal distribution is symmetric about its mean.
so answer c) must be true.
The standard equation of a circle is
(x-h)^2 + (y-k)^2 = r^2
where the center is at point (h,k)
From the statement of the problem, it is already established that h = 2 and k = -5. What we have to determine is the value of r. This could be calculated by calculating the distance between the center and point (-2,10). The formula would be
r = square root [(x1-x2)^2 + (y1-y2)^2)]
r = square root [(2--2)^2 + (-5-10)^2)]
r = square root (241)
r^2 = 241
Thus, the equation of the circle is