Three and more points are collinear
The limit does not exist. Why? Because the left hand limit DOES NOT equal the right hand limit. Let’s double check:
We could use -0.000001 to represent the left hand limit. This is less than 0. We plug in 5x - 8
5(-0.000001) - 8
-0.000005 - 8
-8.000005
If we would continue the limit (extend the zeros to infinity), we would get exactly
-8
That is our left hand limit.
Our right hand limit will be represented by 0.000001. This is greater than 0. We plug in abs(-4 - x)
abs(-4 - (0.000001))
abs(-4.000001)
4.000001
If we would continue the limit (extend the zeros to infinity), we would get exactly
4
4 does not equal -8, therefore
The limit does not exist
Answer:
-3
Step-by-step explanation:
to eliminate 6x we need the same no. 6x but that should be negative. so
2X × -3 = -6X
and
6X+(-6X)=0
The answer is all nonzero real numbers. I've had this problem before
Answer:
x intercept (15/4,0)
y intercept (0,2)
slope 8/15
Step-by-step explanation:
15y − 8x = 30.
To find the x intercept, set y =0
15(0) -8x = 30
8x = 30
Divide each side by 8 to solve for x
8x/8 = 30/8
x = 15/4
To find the y intercept, set x =0
15y -8(0) = 30
15y = 30
Divide each side by 15
15y/15 = 30/15
y =2
To find the slope we solve the equation for y
15y − 8x = 30.
Add 8x to each side
15y − 8x+8x =8x +30.
15y = 8x +30
Divide each side by 15
15y/15 = 8x/15 +30/15
y = 8/15x +2
The slope is 8/15
