The first one is b the second one is b too
Count the number of multiples of 3, 4, and 12 in the range 1-2005:
⌊2005/3⌋ ≈ ⌊668.333⌋ = 668
⌊2005/4⌋ = ⌊501.25⌋ = 501
⌊2005/12⌋ ≈ ⌊167.083⌋ = 167
(⌊<em>x</em>⌋ means the "floor" of <em>x</em>, i.e. the largest integer smaller than <em>x</em>, so ⌊<em>a</em>/<em>b</em>⌋ is what you get when you divide <em>a</em> by <em>b</em> and ignore the remainder)
Then using the inclusion/exclusion principle, there are
668 + 501 - 2•167 = 835
numbers that are multiples of 3 or 4 but not 12. We subtract the number multiples of 12 twice because the sets of multiples of 3 and 4 both contain multiples of 12. Subtracting once removes the multiples of 3 <em>and</em> 4 that occur twice. Subtracting again removes them altogether.
Answer:
x = 3/5
Step-by-step explanation:
4+4(x-2)=2(x+1)−x
Distribute
4+4x-8 = 2x+1-x
Rearrange and Simplify
4x - 4 = x + 1
Subtract x and add 4
3x = 5
Divide
x = 3/5
Answer: Intercept of the equation = (9,0)
Charge remaining in Lauren's battery is 0 after 9 hours( since Lauren left her house)
Step-by-step explanation:
Given: When t= the number of hours since Lauren left her house, the charge remaining in Lauren's battery, as a percentage, can be modeled by the equation B=63-7t .
To find the x-intercept, put B =0 (as x denoted the independent variable , here independent variable is 't')
Hence, the x-intercept of the equation = (9,0)
i.e. Charge remaining in Lauren's battery is 0 after 9 hours( since Lauren left her house)
Answer:
Step-by-step explanation:
Interesting question
They form at right angles. The reason is the highways meet at right angles is that the United States does something really interesting and well thought out with its highway system.
The odd numbers run North and South
The even numbers run East and West.
So I-75 runs North and South
I-80 runs East and West.
They will, when they meet, form a right angle. This works for the interstates, but there a system for the intrastates as well.
I wish Canada would do something like that.
