The high school has 26 teachers and 546 students. What is the ratio of teachers to students?
1 answer:
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Answer:
Question 1:
The angles are presented here using Autocad desktop application
The two column proof is given as follows;
Statement Reason
S1. Line m is parallel to line n R1. Given
S2. ∠1 ≅ ∠2 R2. Vertically opposite angles
S3. m∠1 ≅ m∠2 R3. Definition of congruency
S4. ∠2 and ∠3 form a linear pear R4. Definition of a linear pair
S5. ∠2 is supplementary to ∠3 R5. Linear pair angles are supplementary
S6. m∠2 + m∠3 = 180° Definition of supplementary angles
S7. m∠1 + m∠3 = 180° Substitution Property of Equality
S8. ∠1 is supplementary to ∠3 Definition of supplementary angles
Question 2:
(a) The property of a square that is also a property of a rectangle is that all the interior angles of both a square and a rectangle equal
(b) The property of a square that is not necessarily a property of all rectangles is that the sides of a square are all equal, while only the length of the opposite sides of a rectangle are equal
(c) The property of a rhombi that is also a property of a square is that all the sides of a rhombi are equal
(d) A property of a rhombi that is not necessarily a property of all parallelogram is that the diagonals of a rhombi are perpendicular
(e) A property that applies to all parallelogram is that the opposite sides of all parallelogram are equal
Step-by-step explanation:
To get started, we will use the general formula for bacteria growth/decay problems:
where:
A_{f} = Final amount
A_{i} = Initial amount
k = growth rate constant
t = time
For doubling problems, the general formula can be shortened to:
Now, we can use the shortened formula to calculate the growth rate constant of both bacteria:
Colby (1):
per hour
Jaquan (2):
per hour
Using Colby's rate constant, we can use the general formula to calculate for Colby's final amount after 1 day (24 hours).
Note: All units must be constant, so convert day to hours.
Remember that the final amount for both bacteria must be the same after 24 hours. Again, using the general formula, we can calculate the initial amount of bacteria that Jaquan needs:
where:
A_{f} = Final amount
A_{i} = Initial amount
k = growth rate constant
t = time
For doubling problems, the general formula can be shortened to:
Now, we can use the shortened formula to calculate the growth rate constant of both bacteria:
Colby (1):
Jaquan (2):
Using Colby's rate constant, we can use the general formula to calculate for Colby's final amount after 1 day (24 hours).
Note: All units must be constant, so convert day to hours.
Remember that the final amount for both bacteria must be the same after 24 hours. Again, using the general formula, we can calculate the initial amount of bacteria that Jaquan needs: