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Reptile [31]
3 years ago
14

The area of ​​the bottom of the two cylindrical vessels A and B is 400cm ^ 2 and 300cm ^ 2, respectively. A jar is about 6cm hig

h and the B jar has 420 ml of water. If the water in the A jar is completely poured into the B bowl, how high will the water in the B container be?
NEED THE STEP BY STEP EXPLANATION...WILL GIVE THE BRAINLIEST.​

Mathematics
1 answer:
Sonbull [250]3 years ago
4 0

Answer:

Water in container B will be at 6.own

Step-by-step explanation:

calculate the volume in cont. A

VoA=400×6

=2400cm cube

VoB=420ml

=420cm cube [1ml=1cm cube]

now add both volumes

V=2400+420

=2820cm cube

Now,

2820 cm cube in jar B so

2820=420×h

h=6.71

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5 0
2 years ago
A model rocket is launched with an intitial upupward velocity of 202 ft/s. The rocket’s height h (in feet) after seconds is give
dsp73

Given that the height of a object thrown within a gravitational field is given as a quadratic equation in time, <em>t</em>, the time at which the object is at a specified height can be found by the quadratic formula

The values of, <em>t</em>, for which the height of the rocket is 82 feet are;

t = 12.21 seconds or t = 0.42 seconds

Question: <em>Parts of the question that appear missing but can be found online are (i) To find the values of the time, t, when the rocket's height is 82 feet and round answers to the nearest hundredth</em>

The known parameters of the rocket are;

The initial upward velocity of the rocket, v = 202 ft./s

The given function representing the height, <em>h</em>, (in feet) after <em>t</em> seconds is presented as follows;

H = 202·t - 16·t²

The unknown;

The time for which the height of the rocket is 82 feet

Method;

Substitute H = 82 feet in the height function equation and solve for <em>t</em> as follows;

When H = 82, we get;

82 = 202·t - 16·t²

Therefore;

16·t² - 202·t + 82 = 0

Dividing the above equation by <em>2</em> gives;

(16·t² - 202·t + 82)/2 = 0/2

8·t² - 101·t + 41 = 0

By using the quadratic formula, we get;

\mathbf{t = \dfrac{101 \pm \sqrt{(-101)^2 - 4 \times 8 \times 41} }{2 \times 8}  =  \dfrac{101 \pm \sqrt{8889} }{16}}

Therefore, the values of <em>t</em> given by rounding off to the nearest hundredth are;

t = 12.21 or t = 0.42

The values of the time, <em>t</em>, at which the height of the rocket is 82 feet are t = 12.21 seconds or t = 0.42 seconds

Learn more about equation models of height as a function of time here;

brainly.com/question/84352

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Answer:

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Hope this helps!!

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Answer:

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