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Pani-rosa [81]
3 years ago
5

ken paid $12 for two magazines. The cost of each magazine was a multiple of $3. What are the possible prices of the magazines?

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
6 0
<span>The possible price of the magazine can be either $ 9 , $ 6 , or $3 First we need to understand the different between a cost and a price. A cost is the amount of money needed to Produce the magazine, while a price is the amount of money that the sellers get when he hand it over to customer since its said the cost is in multiple of $ 3 , the possible price of two magazine would be : $ 9 + $3 = $ 12 $6 + $6 = $ 12 $3 + $ 9 = $ 12</span>
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Number 10 plzz???????
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3 years ago
Three consecutive integers whose sum is -147
suter [353]

Step-by-step explanation:

Let the first integer be x

2nd integer = x + 1

3rd integer = x + 2

x + x + 1 + x + 2 = -147

3x + 3 = -147

3x = -147 - 3

3x = -150

x = -150 ÷ 3

x = -50

The three consecutive integers are

-50, -49, -48

5 0
3 years ago
Solve.
Nikitich [7]
The answer is C: 10\text{ }^1/_2. Here are the details:

\text{Equation:}\\ 6\text{ }^1/_3+10\text{ }^1/_2\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{Start with the integers.}\\ 6+10=16\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{...then with the fractions, but rewrite them first to make it easier.}\\ ^1/_3+\text{ }^1/_2\stackrel{\text{rewrite}}{\to}\text{ }^2/_6+\text{ }^3/_6=\text{ }^5/_6\stackrel{?}{=}26\text{ }^1/_6\\&#10;\\&#10;\text{Add 'em up!}\\&#10;16\text{ }^5/_6

\text{Equation:}\\&#10;16\text{ }^5/_6+3\text{ }^5/_6\stackrel{?}{=}26\text{ }^1/_6\\&#10;\\&#10;\text{Start with the integers.}\\&#10;16+3=19\stackrel{?}{=}26\text{ }^1/_6\\&#10;\\&#10;\text{...then with the fractions, but rewrite them first to make it easier.}\\&#10;^5/_6+\text{ }^5/_6=\text{ }^{10}/_6\stackrel{\text{rewrite}}{\to}\text{ }^5/_3\stackrel{\text{rewrite}}{\to}1\text{ }^2/_3\stackrel{?}{=}26\text{ }^1/_6\\&#10;\\&#10;\text{Add 'em up!}\\&#10;20\text{ }^2/_3

\text{Last equation:}\\ 20\text{ }^2/_3+5\text{ }^1/_2\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{Start with the integers.}\\ 20+5=25\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{...then with the fractions, but rewrite them first to make it easier.}\\ ^2/_3+\text{ }^1/_2\stackrel{\text{rewrite}}{\to}\text{ }^4/_6+\text{ }^3/_6=\text{ }^7/_6\stackrel{\text{rewrite}}{\to}1\text{ }^1/_6\stackrel{?}{=}26\text{ }^1/_6\\&#10;\\&#10;\text{Add the integer and fraction together.}\\&#10;25+1\text{ }^1/_6\stackrel{?}{=}26\text{ }^1/_6

26\text{ }^1/_6\stackrel{\checkmark}{=}26\text{ }^1/_6
5 0
3 years ago
I think the answer is c can someone check me
Katen [24]

Answer:

D

Step-by-step explanation:

you first have to find the domain by finding where the expression is defined

so the answer would be x>5

6 0
3 years ago
What is the value of the six in 106,534
aleksley [76]
6,000 because its in the thousandth and so since its a six in the thousandths its 6,000 remember the comma
8 0
3 years ago
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