Given:
The equation of a circle is
A tangent line l to the circle touches the circle at point P(12,5).
To find:
The gradient of the line l.
Solution:
Slope formula: If a line passes through two points, then the slope of the line is
Endpoints of the radius are O(0,0) and P(12,5). So, the slope of radius is
We know that, the radius of a circle is always perpendicular to the tangent at the point of tangency.
Product of slopes of two perpendicular lines is always -1.
Let the slope of tangent line l is m. Then, the product of slopes of line l and radius is -1.
Therefore, the gradient or slope of the tangent line l is 
.
So when you reflect the x-axis, you change the y negative. So (x,y) would be (x,-y). so it would be (-2, -6). If you want to reflect over the y-axis, it would be (-x, y).
Answer:
Step-by-step explanation:
4.5 miles
We want to determine the equation in point slope form for the line that is perpendicular to the given line and passing through the point (5.6) .
The equation and the point is;
We know that for two lines to be perpendicular, the product of their slopes should be -1.
Therefore, the slope of the perpendicular should be;
The second condition is that the line must pass through the point (5,6) , to do thid, we write the equation of the line in point slope form which is;
Inserting all values, we have,
That is the final answer.
Can you show the multiple choice one
