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3 years ago

What is the result of 3 divided by 1/6

Mathematics

2 answers:

Greeley [361]3 years ago

6 0

Your answer would be 18

Sholpan [36]3 years ago

5 0

3 divided by 1/6=3/1 / 1/6=3/1 * 6/1=3*6=18

18 is the answer

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Carlos finds the absolute value of -5.3, and then finds the opposite of his answer. Jason finds the opposite of -5.3 and then fi

polet [3.4K]

The absolute value is how far away a number is from the number line, so it is always positive. If Carlos finds the opposite of the absolute value, that means he found the negative version. So Jason's final value will be greater.

4 0

3 years ago

Read 2 more answers

Leah claims that these figures are not similar. When she compared the heights, she wrote 27. Then she compared the bases and got

Flauer [41]

Answer:

<h2>Leah is actually wrong, because those rectangles are similar.</h2>

Step-by-step explanation:

Remember that similarity is about having proportional sides and congruent angles. When we have congruent sides, then those rectangles are congruent not similar.

In this case, to find the similarity, Leah should compare bases and heights thorugh division, because the ratio between heights and the ratio between bases must be equal. So, let's divide.

$\frac{21}{6}=3.5$

$\frac{7}{2}=3.5$

As you can observe, both ratios are equal.

Therefore, those rectangles are congruent.

4 0

3 years ago

Write an equation of the line passing through the points (4,6) and (-2, - 18).

olga_2 [115]

Answer:

y = 4x – 10

Step-by-step explanation:

slope formula: $m = \frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

point-slope formula: $y-y_{1}=m\left(x-x_{1}\right)$

Use slope formula and plug in your numbers: $m = \frac{-18-6}{-2-4 }$
Solve for slope $m = 4$
Use the point-slope formula to solve for the equation: $y-6=4\left(x-4\right)$
Solve and find equation: $y=4x-10$

Note: When given two points you only need to pick one for the point-slope formula! Best to choose the positive one so you don't have to deal with the negatives!

Hope this helps! Please give Brainliest!

4 0

3 years ago

Find the Maclaurin series for f(x) using the definition of a Maclaurin series. [Assume that f has a power series expansion. Do n

aliya0001 [1]

Answer:

$f(x)=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}$

Step-by-step explanation:

The Maclaurin series of a function f(x) is the Taylor series of the function of the series around zero which is given by

$f(x)=f(0)+f^{\prime}(0)x+f^{\prime \prime}(0)\dfrac{x^2}{2!}+ ...+f^{(n)}(0)\dfrac{x^n}{n!}+...$

We first compute the n-th derivative of $f(x)=\ln(1+2x)$ , note that

$f^{\prime}(x)= 2 \cdot (1+2x)^{-1}\\f^{\prime \prime}(x)= 2^2\cdot (-1) \cdot (1+2x)^{-2}\\f^{\prime \prime}(x)= 2^3\cdot (-1)^2\cdot 2 \cdot (1+2x)^{-3}\\...\\\\f^{n}(x)= 2^n\cdot (-1)^{(n-1)}\cdot (n-1)! \cdot (1+2x)^{-n}\\$

Now, if we compute the n-th derivative at 0 we get

$f(0)=\ln(1+2\cdot 0)=\ln(1)=0\\\\f^{\prime}(0)=2 \cdot 1 =2\\\\f^{(2)}(0)=2^{2}\cdot(-1)\\\\f^{(3)}(0)=2^{3}\cdot (-1)^2\cdot 2\\\\...\\\\f^{(n)}(0)=2^n\cdot(-1)^{(n-1)}\cdot (n-1)!$

and so the Maclaurin series for f(x)=ln(1+2x) is given by

$f(x)=0+2x-2^2\dfrac{x^2}{2!}+2^3\cdot 2! \dfrac{x^3}{3!}+...+(-1)^{(n-1)}(n-1)!\cdot 2^n\dfrac{x^n}{n!}+...\\\\= 0 + 2x -2^2 \dfrac{x^2}{2!}+2^3\dfrac{x^3}{3!}+...+(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}+...\\\\=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^n\dfrac{x^n}{n}$

3 0

3 years ago

Question 3

gladu [14]

The answer is a) 16.

5 0

3 years ago