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Natalka [10]
3 years ago
9

6 × 10E2 as a standard notation

Mathematics
2 answers:
Allisa [31]3 years ago
7 0

Answer:

600

Step-by-step explanation:

6x10^2 = 600

lara [203]3 years ago
6 0

Answer:

600

Step-by-step explanation:

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Find all real and imaginary zeros 1.) 343x^3-8=0 2.) 64x^3=0
puteri [66]
1.                                                                  343x³ - 8 = 0
                             343x³ + 98x² - 98x² + 28x - 28x - 8 = 0
                             343x³ + 98x² + 28x - 98x² - 28x - 8 = 0
    7x(49x²) + 7x(14x) + 7x(4) - 2(49x²) - 2(14x) - 2(4) = 0
                       7x(49x² + 14x + 4) - 2(49x² + 14x + 4) = 0
                                              (7x - 2)(49x² + 14x + 4) = 0
                                  7x - 2 = 0    or    49x² + 14x + 4 = 0
                                      + 2 + 2           x = -(14) ± √((14)² - 4(49)(4))
                                       7x = 2                               2(49)
                                        7     7           x = -14 ± √(196 - 784)
                                         x = ²/₇                           98
                                                            x = -14 ± √(-588)
                                                                         -98
                                                            x = -14 ± 14i√(3)
                                                                         -98
                                                            x = -14 + 14i√(3)  or  x = -14 - 14i√(3)
                                                                         -98                            -98
                                                            x = ¹/₇ - ¹/₇i√(3)  or  x = ¹/₇ + ¹/₇√(3)
                                                            x = ¹/₇ ± ¹/₇i√(3)
                                        Solution Set: {¹/₇ ± ¹/₇i√(3), ²/₇}

2. 64x³ = 0
     64     64
        x³ = 0
   ∛(x³) = ∛(0)
         x = 0
Solution Set: {0}
6 0
4 years ago
If ƒ(x ) = x 2 + 1 and g(x ) = 3x + 1, find ƒ(-1) + 5g(-3).<br><br> -40<br> -38<br> 7
EastWind [94]
f(x) = x^2 + 1 \\ &#10;g(x) = 3x + 1

You can do this in parts.
f(-1) = (-1)^2 + 1 = 1 + 1 = 2
g(-3) = 3(-3) + 1 = -9 + 1 = -8
So, 5g(-3) = 5(-8) = -40.
So f(-1) + 5g(-3) = 2 - 40 = -38

Or you can do this as one big chunk.
f(-1) + 5g(-3)
=[(-1)^2+1] + 5[3(-3) + 1] \\&#10;= (2) + 5(-9 + 1) \\&#10;= 2 + 5(-8) \\&#10;= 2 - 40 \\ = -38
7 0
3 years ago
Read 2 more answers
If you roll two fair six-sided dice, what is the probability that the dice show the same number?
snow_lady [41]

Answer:

mom will let you know

Step-by-step explanation:

shes gone

6 0
3 years ago
Read 2 more answers
Evaluate each expression if a = 6, b = 3, and c = 2.
cricket20 [7]

Answer:

1=6 2=3 4=1 5=5 6=4 7=18 8=8

7 0
4 years ago
Based on the information below, what are the values of x and y of the solution to the system of equations used to create the
ryzh [129]

Answer:

What is the x-value of the solution to the system of equations shown below?

Step-by-step explanation:

y = 3x +5

2y = 4x + 24

6 0
4 years ago
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