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Alex73 [517]
3 years ago
10

Start time: Elapsed time: 9 3/4 End time: 6:00 P.M.

Mathematics
1 answer:
docker41 [41]3 years ago
8 0
Answer: 8:15 Have a nice day!
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3. A magical four-sided die is rolled twice. Let S be the sum of the resultsof the two rolls. We are told that the probability t
Fed [463]

Answer:

P(S=k) = (1/35)k

8/21

Step-by-step explanation:

P(S=k) is proportional to k

P(S=k) = ck

Total probability is 1

k = 2,3.... 8

Sum of all probabilities =

2c + 3c + 4c + 5c + 6c + 7c + 8c = 1

35c = 1

c = 1/35

P(S=k) = (1/35)k, where k = 2,3,...8

P(1&1):

P(S=2) = 2/35

P(2&2):

P(S=4)/3 = (1/3)(4/35) = 4/105

Because for S=4: (1,3) (2,2) (3,1) and all are equally likely

P(3&3):

P(S=6)/3 = (1/3)(6/35) = 2/35

Because for S=6: (2,4) (3,3) (4,2)

P(4&4):

P(S=8) = 8/35

P(getting doubles = 2/35 + 4/105 + 2/35 + 8/35 = 40/105 = 8/21

6 0
4 years ago
The volume of a cone, V, is represented by , where r is the cone’s radius and h its height.
Arlecino [84]
So the height will equal 95.50 inches.

So if you double the height the volume is 1800cm3 and that is double the original volume 

And if you double the height the volume is 3600cm3 and that is the triple the original volume 
8 0
3 years ago
Attend to precision. Mimi says that the 16 is 4.<br> Is Mimi correct? Explain.
garri49 [273]

Answer: It depends on the terms.

Step-by-step explanation: In fraction terms 16 is equivalent to 4. In number terms 16 is a number larger than 4.

8 0
3 years ago
Prove tan(θ / 2) = sin θ / (1 + cos θ) for θ in quadrant 1 .
Leona [35]
We are asked to prove tan(θ / 2) = sin θ / (1 + cos θ). In this case, tan θ is equal to sin θ / cos θ. we can apply this to the equality. sin θ is equal to square root of (1-cos θ)/2 while cos θ is equal to <span>square root of (1 + cos θ)/2.
Hence, when we replace cos </span><span>θ with </span>square root of (1-cos θ)/2, we can prove already.
3 0
3 years ago
Read 2 more answers
you put 500$ in your bank account. With an intrest rate of 5% how long will it take for the account to reach 600$?
Sergeeva-Olga [200]
4 1/2 years
hope this helped
3 0
3 years ago
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