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4 years ago

15 14 18 24 10 55 14 19 Find the mean, median and mode

Mathematics

1 answer:

Charra [1.4K]4 years ago

5 0

Answer:

Mean: 21.125

Median: 16.5

Mode: 14

Step-by-step explanation:

First sourt your numbers from smallest to biggest - very important!

Mean= (all numbers total/amount of numbers)=169/8=21.125

Median= The middle two numbers added and divided by two = 15+18/(2)=16.5

Mode=number that appears most often: 14 appears twice!

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ArbitrLikvidat [17]

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3 years ago

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Cloud [144]

Answer:

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3 years ago

Your friend, Susannah, manages a sandwich shop. She collects data on the number of turkey sandwiches sold per day for a week. Ex

ExtremeBDS [4]

Susannah's data are illustration of measure of central tendencies

(a) The mean

To calculate the mean, she needs to divide the total number of turkey sandwiches sold, by the number of days.

The total is:

$\mathbf{Total = 73 +88+85+88+99+134+129}$

$\mathbf{Total = 696}$

The number of days is:

$\mathbf{Day = 7}$

So, the mean is:

$\mathbf{Mean =\frac{Total}{Days}}$

$\mathbf{Mean =\frac{696}{7}}$

$\mathbf{Mean =99.4}$

Hence, the mean number of turkey sandwiches sold is 99.4

(b) The median

To calculate the median, she needs to arrange the data in ascending or descending order, then select the middle item.

In ascending order, we have: 73, 85, 88, 88, 99, 129, 134

The middle item is 88

So:

$\mathbf{Median = 88}$

Hence, the median number of turkey sandwiches sold is 88

(c) The mode

This is the data that occurs most.

From the dataset, 88 appears twice (more than others).

So:

$\mathbf{Mode = 88}$

Hence, the mode number of turkey sandwiches sold is 88

(d) The range

This is the difference between the highest and least data

From the dataset,

The highest is 134, and the least is 73

So:

$\mathbf{Range =134 - 73}$

$\mathbf{Range =61}$

Hence, the range of turkey sandwiches sold is 61

The measure that would be most helpful is the median, because it is not affected by outliers.

Read more about measures of central tendencies at:

brainly.com/question/5495004

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3 years ago

A small manufacturing firm has 250 employees. Fifty have been employed for less than 5 years and 125 have been with the company

sukhopar [10]

Answer:

Step-by-step explanation:

Given that a small manufacturing firm has 250 employees. Fifty have been employed for less than 5 years and 125 have been with the company for over 10 years. So remaining 75 are between 5 and 10 years.

Suppose that one employee is selected at random from a list of the employees

A) Probability that the selected employee has been with the firm less than 5 years = $\frac{50}{250 } \\= 0.20$