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miskamm [114]
3 years ago
9

When do you get an answer to a system of linear equations that has one solution, no solution and infinitely many solutions?

Mathematics
1 answer:
meriva3 years ago
6 0

Answer:

Step-by-step explanation:

One solution:  when two lines intersect in exactly one point.

Infinitely many solutions:  When one of two lines can be shown algebraically to be exactly the same as the other.  The two lines coincide.

No solution:  The two lines have the same slope but different y -intercepts.  They can't and don't intersect.

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Use the properties of exponents to simplify the expression: y^(y3)2
iren [92.7K]

because y^3 is raised to the power of two, we will have to multiply the exponents rather than adding them.

By distributing the power of 2, we will get y^2(6).

Because now the exponents are being multiplied, we can just add them to get y^8. The other y has a power of 1, so we'll just add the power of that y as well to get y^9.

summary:

multiply exponents if they are being raised to a power.

add exponents if they are being multiplied, and only add them if they have the same base (in this case, both the bases of the exponents are y, so we can add them)

8 0
3 years ago
Randy rented a rectangular storage shed with the volume of 357 ft does it sheds height is 8 and 1/2 ft and the width of is 6 ft
ollegr [7]

Answer:

7 feets

Step-by-step explanation:

Volume of shed, V = 357 feet³

Height of shed, H= 8 1/2 fts

Width of shed, W = 6 ft

Using the relation :

Volume = Length * width * height

357 = L * 6 ft * 17/2 feets

357 feets³ = L * 51 feets²

L = 357 feets³ / 51 feets²

Length, L = 7 feets

7 0
2 years ago
73 divi by 844<br> helppppppppppppp
Mice21 [21]

Answer:

0.1

Step-by-step explanation:

73/844=0.08649=0.1(After rounding)

6 0
2 years ago
Prove that an = 4^n + 2(-1)^nis the solution to
olga nikolaevna [1]

Answer:

See proof below

Step-by-step explanation:

We have to verify that if we substitute a_n=4^n+2(-1)^n in the equation a_n=3a_{n-1}+4a_{n-2} the equality is true.

Let's substitute first in the right hand side:

3a_{n-1}+4a_{n-2}=3(4^{n-1}+2(-1)^{n-1})+4(4^{n-2}+2(-1)^{n-2})

Now we use the distributive laws. Also, note that (-1)^{n-1}=\frac{1}{-1}(-1)^n=(-1)(-1)^{n} (this also works when the power is n-2).

=3(4^{n-1})+6(-1)^{n-1}+4(4^{n-2})+8(-1)^{n-2}

=3(4^{n-1})+(-1)(6)(-1)^{n}+4^{n-1}+(-1)^2(8)(-1)^{n}

=4(4^{n-1})-6(-1)^{n}+8(-1)^{n}=4^n+2(-1)^n=a_n

then the sequence solves the recurrence relation.

4 0
3 years ago
What is the value of 3(y + 4) – (x – 1) when x = 3 and y = 2
olga_2 [115]

Answer:

16

Step-by-step explanation:

First, substitute the values of the variables into the expression:

3(y + 4) - (x - 1)

3(2 + 4) - (3 - 1)

Now, simplify both parentheses:

3(6) - 2

18 - 2

Finally, simplify:

16

7 0
3 years ago
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