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miskamm [114]
3 years ago
9

When do you get an answer to a system of linear equations that has one solution, no solution and infinitely many solutions?

Mathematics
1 answer:
meriva3 years ago
6 0

Answer:

Step-by-step explanation:

One solution:  when two lines intersect in exactly one point.

Infinitely many solutions:  When one of two lines can be shown algebraically to be exactly the same as the other.  The two lines coincide.

No solution:  The two lines have the same slope but different y -intercepts.  They can't and don't intersect.

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Appropriate units
Novosadov [1.4K]

Answer:

"$/km"

Step-by-step explanation:

He wants to model "maintenance cost" with respect to "distance"

Normally,

maintenance cost would be in currency --- dollars, pounds etc.

distance would be in kilometers, miles, meters etc.

We need to find the ratio that has the COST on top and DISTANCE on bottom

Looking at the choices,

We can eliminate 1st and 3rd immediately as it doesn't have COST on top.

That leaves us with

$/km

and

km/$

$ is in fact currency and unit for cost and km is in fact unit for distance. We need the ratio that has $ on top and km on bottom, that's the 2nd option.

So, $/km is the appropriate unit.

4 0
3 years ago
Read 2 more answers
A chemical company makes two brands of antifreeze. The first brand is 60% pure antifreeze, and the second brand is 85% pure anti
rjkz [21]

Let’s say we have x gallons of brand 1 antifreeze and y gallons of brand 2 antifreeze. We know we need a total of 140 gallons, so one equation to relate the variables would be x+y=140. We also know that our final mixture should have 60% antifreeze, so another equation would be the weighted average of the two brands: .55x+.80y140=.60. (The weighted average is basically multiplying each % (55 and 80) by the number of gallons you have (x and y


) and adding those together, and dividing that by the total number of gallons (140). This equals the % of the final mixture (60).)


Now we have a system of two equations that we can solve.


x+y=140


.55x+.80y140=.60


*rearrange first equation to solve for y


:


y=140−x


*substitute this value in for y


in the second equation:


.55x+.80(140−x)140=.60


*use algebra and solve for x


:


The algebra shouldn’t be too complex, and I’m hoping you’re asking this about the setup rather than the actual algebra, and I’m lazy, and I used a calculator to solve this, and this is probably a long run-on sentence, and I got x=112


.


*plug this in to first equation and solve for y


:


y=140−112=28


x=112,y=28


112 gallons of brand 1 antifreeze, 28 gallons of brand 2 antifreeze. That’s a whole lot of antifreeze.

thanx heyaaaaaa

3 0
3 years ago
Determine the intercepts of the line that correspond to the following table of values
almond37 [142]
Find the equation

alrighty, the slope is rise/run

from (21,-3) to (28,-1)
rise is from -3 to -1 or a rise of 2
run is form 21 to 28 or a run of 7


so slope is 2/7

y=2/7x+b
find b which is the y intercept
alirhgty
use (21,-3)
x=21 and y=-3
-3=(2/7)(21)+b
-3=42/7+b
-3=6+b
-9=b

y=2/7x-9

the y intercept is (0,-9
the x intercept is where y=0

0=2/7x-9
9=2/7x
63/2=x

x intercept is (63/2,0) or (31.5,0)
y intercept is (0,-9)
7 0
4 years ago
Write the point-slope equation for each line with the given slope and point. y –y1 = m(x – x1) Slope = 5 Point on line = (–1, 3)
snow_lady [41]

Answer:

y-3=5(x+1)

Step-by-step explanation:

Point-Slope form is: y-y_1=m(x-x_1)

'm' - Slope

(x1, y1) - Point Coordinate

We are given the point of (-1,3) and the slope of 5.

Replace 'm' with 5, 'x1' with -1, and 'y1' with 3:

y-y_1=m(x-x_1)\rightarrow\boxed{y-3=5(x+1)}

4 0
4 years ago
3) A data set has 11 numbers in it. Each number is a whole number and there are no repeats. The bottom 2 values of the data set
NNADVOKAT [17]

C) 18 is your answer

Hope this brings you luck ^o^ ^_^

7 0
3 years ago
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