All categories

3 years ago

Can someone help with this his math question please

Mathematics

1 answer:

bija089 [108]3 years ago

8 0

Vertex N is at (6, 5), so if we translate it 6 to the left and 5 down, it will be at the origin. Therefore, the correct answer is choice D. None of the other options will put any vertex of the rectangle at the origin.

You might be interested in

Consider the function represented by the

Jobisdone [24]

Answer:

y -5×8=

3-40

setahu saya

Step-by-step explanation:

I hope you

i'm sorry ya kalo jawaban nya salah

8 0

3 years ago

SOMEONE HELP ???? Select steps that could be used to solve the equation 1+ 3x = -x+4

Alex

Answer:

a) add x , subtract 1 and divide by 4

The solution of given equation $x = \frac{3}{4}$

Step-by-step explanation:

Given equation 1+3 x = -x +4

Add 'x' on both sides , we get

1 + 3 x + x = - x + x +4

1 + 4 x = 4

Subtract '1' on both sides , we get

1+4 x -1 = 4 -1

4 x = 3

Dividing '4' on both sides, we get

$\frac{4x}{4} = \frac{3}{4}$

$x = \frac{3}{4}$

Final answer:-

The solution of given equation $x = \frac{3}{4}$

5 0

3 years ago

You are given the parametric equations x=2cos(θ),y=sin(2θ). (a) List all of the points (x,y) where the tangent line is horizonta

vladimir1956 [14]

Answer:

The solutions listed from the smallest to the greatest are:

x: $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$ $\sqrt{2}$

y: -1 1 -1 1

Step-by-step explanation:

The slope of the tangent line at a point of the curve is:

$m = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }$

$m = -\frac{\cos 2\theta}{\sin \theta}$

The tangent line is horizontal when $m = 0$ . Then:

$\cos 2\theta = 0$

$2\theta = \cos^{-1}0$

$\theta = \frac{1}{2}\cdot \cos^{-1} 0$

$\theta = \frac{1}{2}\cdot \left(\frac{\pi}{2}+i\cdot \pi \right)$ , for all $i \in \mathbb{N}_{O}$

$\theta = \frac{\pi}{4} + i\cdot \frac{\pi}{2}$ , for all $i \in \mathbb{N}_{O}$

The first four solutions are:

x: $\sqrt{2}$ $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$

y: 1 -1 1 -1

The solutions listed from the smallest to the greatest are:

x: $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$ $\sqrt{2}$

y: -1 1 -1 1

6 0

3 years ago

What is the volume of a cylinder with a diameter equal to 6 and height equal to 8? Let pi = 3.14.

Sindrei [870]

Volume of a cylinder is pi*(radius)^2* height. pi is 3.14 and radius is half of diameter which would be 3. height is 8. Thus volume of a cylinder in your case is pi*9*8 or 72*pi which is approximately 226.19

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%7B9%7D%5E%7B2%7D%20-%202%281%20%2B%203%29" id="TexFormula1" title=" {9}^{2} - 2(1 + 3)" al

Dmitrij [34]

The answer is 73 because you solve 9^ 2 which is 81 then multiply 2 times 4 which is 8 then subtract 81 and 8 which is 73

8 0

3 years ago

Read 2 more answers