Problem 1
x = measure of angle N
2x = measure of angle M, twice as large as N
3(2x) = 6x = measure of angle O, three times as large as M
The three angles add to 180 which is true of any triangle.
M+N+O = 180
x+2x+6x = 180
9x = 180
x = 180/9
x = 20 is the measure of angle N
Use this x value to find that 2x = 2*20 = 40 and 6x = 6*20 = 120 to represent the measures of angles M and O in that order.
<h3>Answers:</h3>
- Angle M = 40 degrees
- Angle N = 20 degrees
- Angle O = 120 degrees
====================================================
Problem 2
n = number of sides
S = sum of the interior angles of a polygon with n sides
S = 180(n-2)
2700 = 180(n-2)
n-2 = 2700/180
n-2 = 15
n = 15+2
n = 17
<h3>Answer: 17 sides</h3>
====================================================
Problem 3
x = smaller acute angle
3x = larger acute angle, three times as large
For any right triangle, the two acute angles always add to 90.
x+3x = 90
4x = 90
x = 90/4
x = 22.5
This leads to 3x = 3*22.5 = 67.5
<h3>Answers:</h3>
- Smaller acute angle = 22.5 degrees
- Larger acute angle = 67.5 degrees
Multiply each of the numbers by a ten to a power that they both become whole numbers.
0.67 *
= 67
0.3 *
= 30
Divide as usual.
67 / 30 = 2
So, the answer is 2 1/3.
Two parallel lines are skew if they are not parallel but are in different planes, which means that they will not intersect, in spite of they are not parallel.
I'm not sure what side is missing but you could use the proportions
A/B=X/Y or B/C=Y/Z or CA/=ZX. it also works if you reverse this for example B/A=Y/X
Answer: 
Step-by-step explanation:
Given
The two communication mask are 2 km apart
Ubi's home is 500 m east of one of the mask
Suppose its distance from the other's is x
From the figure, we can write
