Perimeter = 2L + 2W = 48 WHERE L=length and W=width
The length must be longer than the width so im going to say that L = W + 5
so the equation is
2(W + 5) + 2W = 48
2W + 2W + 10 = 48
4W = 38
W = 38/4 = 9.5 ins and
length = 5+9.5 = 14.5 ins
Answer:
The mean of the sampling distribution of the sample mean alcohol consumption is of 5.70 alcoholic drinks per week and the standard deviation is 0.13 alcoholic drinks per week
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean and standard deviation , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean and standard deviation .
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this problem, we have that:
The mean of the sampling distribution of the sample mean alcohol consumption is of 5.70 alcoholic drinks per week and the standard deviation is 0.13 alcoholic drinks per week
Answer:56 pack
Step-by-step explanation:
Length of backyard(L)=32feet
Width of backyard(W)=21feet
Area of backyard(A)=?
A=32x21
A=672 square feet
Each pack of seed cover 12 square feet
Therefore 672/12pack will be needed to cover the whole area of the backyard
672/12=56 pack will be needed