All categories

2 years ago

How i can answer this question

Mathematics

2 answers:

Setler79 [48]2 years ago

8 0

Hi! You must give your answer in it’s simplest form

So, because 4q and 2q are like terms that would become 6q

Because 3 and 1 are like terms it would be 3-1 which is 2

Therefore your answer is 6q+2

Hope this helps :)

Mars2501 [29]2 years ago

4 0

Answer:

3(2q+1)

Step-by-step explanation:

6q+2

3(2q+1)

You might be interested in

12. In the given figure, RS is parallel to PQ, If RS = 3 cm, PQ = 6 cm and ar(∆TRS) = 15cm³, then ar (∆TPQ) = ? (a) 70 cm² (b) 5

Gnesinka [82]

$\large\underline{\sf{Solution-}}$

Given that,

In triangle TPQ, 

RS || PQ,

RS = 3 cm,

PQ = 6 cm,

ar(∆ TRS) = 15 sq. cm

As it is given that, RS || PQ

So, it means

⇛∠TRS = ∠TPQ [ Corresponding angles ]

⇛ ∠TSR = ∠TPQ [ Corresponding angles ]

$\rm\implies \: \triangle TPQ \: \sim \: \triangle TRS \: \: \: \: \: \: \{AA \}$

Now, We know 

Area Ratio Theorem,

This theorem states that :- The ratio of the area of two similar triangles is equal to the ratio of the squares of corresponding sides.

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{ar( \triangle \: TRS)} = \dfrac{ {PQ}^{2} }{ {RS}^{2} }$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = \dfrac{ {6}^{2} }{ {3}^{2} }$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = \dfrac{36 }{9}$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = 4$

$\rm\implies \:ar( \triangle \: TPQ) = 60 \: {cm}^{2}$

3 0

2 years ago

Complete the following statement. ___ (-9) = -10

g100num [7]

Answer:

-1

Explanation:

X - 9 = -10
+9 +9
——————
X = -1

3 0

3 years ago

4. The numencal coefficient in 3xy is A-3 В 2 D ху Ску

BabaBlast [244]

Answer:

Step-by-step explanation:

Because in 3xy 3 is the numerical coefficient

3 0

3 years ago

Read 2 more answers

1. Suppose you have a variable X~N(8, 1.5). What is the probability that you have values between (6.5, 9.5)

Natalija [7]

Answer:

0.6826 = 68.26% probability that you have values in this interval.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

X~N(8, 1.5)

This means that $\mu = 8, \sigma = 1.5$