To convert a fraction to a decimal , the solution is to divide the numerator by the denominator. Since its a mixed fraction, you already know what the 5/8 of the problem is (0.625). All you do it add the 4 to the decimal and it'll be 4.0625
Answer:
3
Step-by-step explanation:
$25×6.50=152.5
50÷13=0.26
Answer:
The 84% confidence interval for the population proportion that claim to always buckle up is (0.74, 0.80).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
![\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}](https://tex.z-dn.net/?f=%5Cpi%20%5Cpm%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D)
In which
z is the z-score that has a p-value of
.
They randomly survey 387 drivers and find that 298 claim to always buckle up.
This means that ![n = 387, \pi = \frac{298}{387} = 0.77](https://tex.z-dn.net/?f=n%20%3D%20387%2C%20%5Cpi%20%3D%20%5Cfrac%7B298%7D%7B387%7D%20%3D%200.77)
84% confidence level
So
, z is the value of Z that has a p-value of
, so
.
The lower limit of this interval is:
![\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 - 1.405\sqrt{\frac{0.77*0.23}{387}} = 0.74](https://tex.z-dn.net/?f=%5Cpi%20-%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D%20%3D%200.77%20-%201.405%5Csqrt%7B%5Cfrac%7B0.77%2A0.23%7D%7B387%7D%7D%20%3D%200.74)
The upper limit of this interval is:
![\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 + 1.405\sqrt{\frac{0.77*0.23}{387}} = 0.8](https://tex.z-dn.net/?f=%5Cpi%20%2B%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D%20%3D%200.77%20%2B%201.405%5Csqrt%7B%5Cfrac%7B0.77%2A0.23%7D%7B387%7D%7D%20%3D%200.8)
The 84% confidence interval for the population proportion that claim to always buckle up is (0.74, 0.80).
using the formula:
y = mx +b
Using the given slope and coordinate points we get:
-1 = -3(2) + b
-1 = -6 + b
add 6 to each side
5 = b
y = -3x + 5
which is the same as:
3x + y = 5 ...answer choice a
The answer is B
If Shahs class planted 4 more than Wongs class and their total was 36, so subtract 4 from 36 to get the variable (how many trees Wong’s class planted).