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zloy xaker [14]
4 years ago
15

A duck's mass at birth was 0.05 kilogram. The duck gained approximately 0.042 kilogram each week. After how many weeks is the du

ck's mass 0.890 kilogram?
Mathematics
1 answer:
Alex_Xolod [135]4 years ago
4 0
Given that the first mass of the duck is 0.05 kg and it gains weight at a rate of 0.042 kg/week, the equation that would represent this scenario is,
                               y = 0.05 + 0.042x
where y is weight and x is the number of weeks. To determine the number of weeks in which the duck's mass becomes 0.890,   
                            0.890 = 0.05 + 0.042x
The value of x from the equation is 20. 
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I don’t get any of these :/// please help
Natasha2012 [34]

1) From the total of 17 marbles, Jacob takes 2 out at random. There are

\dbinom{17}2=C(17,2)=C^{17}_2=\dfrac{P(17,2)}{2!}=\dfrac{P^{17}_2}{2!}=\dfrac{17!}{2!(17-2)!}=136

possible outcomes of the draw. (Lots of different notations are used for the binomial coefficient; the first one is my preference.) The number of ways to draw exactly 2 orange marbles is

\dbinom70\dbinom{10}2=1\cdot1\cdot45=45

That is, of the 3 red and 4 blue marbles - or the 7 non-orange marbles - we want 0; of the 10 oranges, we want 2.

So the probability of drawing exactly 2 orange marbles is \dfrac{45}{136}\approx0.33.

2) Now Jacob draws 3 marbles, for which there are

\dbinom{17}3=680

possible combinations. The event that Jacob draws at least 1 orange marble is complementary to the event that Jacob draws 0 orange marbles. So if we find the probabilty of drawing 0 oranges, then we subtract this from 1 to find the probability of drawing at least 1.

There are

\dbinom73\dbinom{10}0=35\cdot1=35

possible ways of doing, so the probability of drawing 0 oranges is \dfrac{35}{680}, in turn making the probability of drawing at least 1, 1-\dfrac{35}{680}=\dfrac{645}{680}\approx0.95.

3) This question is kinda ambiguous. It's not clear whether Jacob draws a marble with or without replacement.

If he does return a drawn marble to the bag, then for each draw, there is a \dfrac{10}{17} probability that he draws an orange marble, and a \dfrac7{17} probability of not. The draws are presumably independent of one another, so that the probability of drawing the first orange marble on the fourth attempt would be

\dfrac7{17}\cdot\dfrac7{17}\cdot\dfrac7{17}\cdot\dfrac{10}{17}=\dfrac{3430}{83521}\approx0.041

If no replacements are made, then as non-orange marbles are drawn from the bag, the number of non-oranges and the total number of marbles both decrease by 1. Then the probability of drawing orange on the fourth draw would be

\dfrac{\dbinom71\dbinom61\dbinom51\dbinom{10}1}{\dbinom{17}1\dbinom{16}1\dbinom{15}1\dbinom{14}1}=\dfrac5{136}\approx0.037

If you're supposed to round to the nearest hundredths place, your final answer should be acceptable either way.

4) We want the probability that a boat is made of wood given that it has chrome accents:

P(\text{wood}\mid\text{chrome})=\dfrac{P(\text{wood AND chrome})}{P(\text{chrome})}=\dfrac{70\%}{75\%}\approx93\%

5) We apply the inclusion/exclusion principle:

P(\text{wood OR chrome})=P(\text{wood})+P(\text{chrome})-P(\text{wood AND chrome})

P(\text{wood OR chrome})=90\%+75\%-70\%=95\%

6) The events of a boat having chrome accents and a boat being made of wood are independent if and only if

P(\text{wood AND chrome})=P(\text{wood})\cdot P(\text{chrome)}

But 90\%\cdot75\%=67.5\%\neq70\%, so these two events are not independent.

3 0
3 years ago
A recent study of 28 city residents showed that the mean of the time they had lived at their present address was 9.3 years. The
Lana71 [14]

Answer:

We are 90% confident that the true mean lies between 8..6563 and     9.9437  

Step-by-step explanation:

The mean of your estimate plus and minus the range of that estimate constitutes a confidence interval. Within a specific level of confidence, this is the range of values you anticipate your estimate to fall within if you repeat the test. Confidence is another word for probability.

mean (x) = 9.3                        

standard deviation (s) = 2                        

sample size (n) = 28                        

<u>T- Distribution:</u>

degree of freedom = n - 1 = 28 - 1 = 27    

90% Confidence Interval ==> α = 0.1

critical value, t =  1.703 ( t-table)

standard error, SE = s/√n = 2 /√28 = 0.3780

margin of error, E = t × SE= 1.703 × 0.3780 = 0.6437

Confidence Interval: x ± E = 9.3 ± 0.6437

lower limit: x - E = 9.3 - 0.6437 = 8.6563    

upper limit: x + E = 9.3 + 0.6437 = 9.9437    

Confidence Interval: 8.6563 < µ < 9.9437

<u>Z - Distribution:</u>

Formula: Confidence Interval = x ± z (s/√n)

Sample Mean = s/√n = 2/√28 = 2/5.29 = 0.3781

z = 1.645 (from z - table)

From formula, z (s/√n): 0.3781 x 1.645 = 0.620 (rounded)

x ± 0.62

lower limit: x - 0.62 = 9.3 - 0.62 = 8.68  

upper limit: x + 0.62 = 9.3 + 0.62 = 9.92

Confidence Interval: 8.68 < µ < 9.92

Learn more about Confidence Intervals here: brainly.com/question/2141785

5 0
2 years ago
Will mark BRAINLIST Find the perimeter of the following shape, rounded to the nearest tenth: coordinate plane with quadrilateral
kolbaska11 [484]

Answer:

11.3 units

Step-by-step explanation:

Let's find the length of one of the boxes.

a^2+b^2=c^2\\1^2+1^2=c^2\\1+1=c^2\\2 = c^2\\\\\sqrt{2} = c\\ c = 1.414...

Let's simplify c down to 1.41.

Now, there are 8 of these little boxes for the perimeter, let's multiply.

1.41\cdot8=11.28

That can be simplified to the nearest tenth - 11.3

Hope this helped!

8 0
4 years ago
A=8, b=?, c=16 find the missing side
Ksivusya [100]

Answer:

13.8 I think

Step-by-step explanation:

using the pyrhagorem theorem use the formula c=a2+b2

4 0
3 years ago
This mapping shows a functional relationship.
Amiraneli [1.4K]

Answer:

2

Step-by-step explanation:

Data provided in the question

Domain              Range

x                         f(x)

2                         4

-3                        0

-1                        -1

4                         3

As we know that

x = f(x)

So for domains, the ranges are as follows

f(2) = 4

f(-3) = 0

f(-1) = -1

f(4) = 3

As we can see that when f(4) is there so the value of x = 2

5 0
4 years ago
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