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melamori03 [73]
3 years ago
6

Reading is what grammar element

Mathematics
1 answer:
emmasim [6.3K]3 years ago
7 0
Story Grammar Element
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X/(x-2) + (x-1)/(x+1) = -1 <br><br> How to solve?
kirill115 [55]
Multiply entire equation by (x-2)(x+1) to get rid of the denominators That would lead to X(x+1)+(x-1)(x-2)=-1(x-2)(x+1)
Finally, using distributive property and foil, you would get x^2+x+x^2-3x+2=(-x^2+x+2).2x^2-2x+2=-x^2+x+23x^2-3x=0
3x(x-1)x=0 and x=1

7 0
3 years ago
4). Machine “B” can pack 11 boxes per minute. The factory receives an
Elena L [17]

Answer:

Amount of time would be greater than 95 minutes

Step-by-step explanation:

We are told that machine B can pack 11 boxes per minute.

Thus, this is 11x where x represents number of minutes.

We are told that the factory revives an order of over 1100 boxes and that it had already packed 55.

Thus,the inequality equation is;

11x + 55 > 1100

Solving this;

11x > 1100 - 55

11x > 1045

x > 1045/11

x > 95 minutes

6 0
3 years ago
Look at images below. : ]
Akimi4 [234]

Answer:

1) A

B) 5.818 stops

Step-by-step explanation:

Number One is less than or equal to 21 because the person only has 21 dollars, so she can't spend more than 21.

B can be solved through the equation by first subtracting $5, and then dividing 2.75 by 16.

4 0
3 years ago
HELP ME PLEASE!
shusha [124]

Answer:

Part A) The probability is closer to 0, because is less than 50%

Part B) The probability is closer to 1, because is greater than 50%

Step-by-step explanation:

we know that

The probability of an event is the ratio of the size of the event space to the size of the sample space.  

The size of the sample space is the total number of possible outcomes  

The event space is the number of outcomes in the event you are interested in.  

so  

Let

x------> size of the event space

y-----> size of the sample space  

so

P=\frac{x}{y}

Part A) Is the probability of hitting the black circle inside the target closer to 0 or 1?

In this problem we have

x------> is the area of the black circle

y------> is the total area of the square target

<em>Find the area of black circle</em>

r=3/2=1.5\ units    

x=(3.14)(1.5)^{2} =7.065\ units^{2}

<em>Find the total area of the square target</em>

y=9^{2}=81\ units^{2}

Find the probability

P=\frac{7.065}{81}=0.0872

Convert to percentage

0.0872*100=8.72\%

The probability is closer to 0, because is less than 50%

Part B) Is the probability of hitting the white portion of the target closer to 0 or 1?

In this problem we have

x------> is the area of the white portion of the target

y------> is the total area of the square target

<em>Find the area of the white portion</em>

The area is equal to the area of the square minus the area of the circle

x=81-7.065=73.935\ units^{2}

Find the probability

P=\frac{73.935}{81}=0.9128

Convert to percentage

0.9128*100=91.28\%

The probability is closer to 1, because is greater than 50%

4 0
3 years ago
Please answer this question quickly!
mixer [17]

40 \times 15 = 600 \div 3 = 200m \: and \: the \: formula \: is \: to \: divide \: and \: multipliction
6 0
3 years ago
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