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Stolb23 [73]
4 years ago
6

Assume that f is a one-to-one function. (a) if f(1) = 12, what is f −1(12)

Mathematics
2 answers:
Naya [18.7K]4 years ago
7 0
As it is one-to-one function,<span> f −1(12) = 1</span>
viktelen [127]4 years ago
6 0
F-1(x)  is the inverse of f(x)

The domain of f(x) = range of f(-1)x  and vice-versa.

So f-1(12)  = 1.
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The probability is 50% or half or 1/2
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3 years ago
Boyd grows only tomatoes and raspberries in his garden. Last year, he grew 140 pounds of tomatoes and 60 pounds of raspberries.
nadya68 [22]

Answer:

29%.

Step-by-step explanation:

We have been given that Boyd grew 140 pounds of tomatoes and 60 pounds of raspberries. This year, the production, by weight, of tomatoes declined by 20 percent, and the production, be weight, of raspberries declined by 50 percent.

First of all, we will find the weight of tomatoes and raspberries using the given information.

Since the production, by weight, of tomatoes declined by 20 percent, so this year production of tomatoes is 80% of 140 pounds.

\frac{80}{100}\times 140=0.80\times 140=112

Since the production, be weight, of raspberries declined by 50 percent, so this year production of raspberries is 50% of 30 pounds.

\frac{50}{100}\times 60=0.50\times 60=30

Total production this year: 112+30=142 pounds.

Now, we will percent decrease formula.

\text{Percent decrease}=\frac{\text{Initial value-Final value}}{\text{Initial value}}\times 100

\text{Percent decrease}=\frac{(140+60)-142}{140+60}\times 100

\text{Percent decrease}=\frac{(200)-142}{200}\times 100

\text{Percent decrease}=\frac{58}{200}\times 100

\text{Percent decrease}=0.29\times 100

\text{Percent decrease}=29

Therefore, the total yield, by weight, of Boyd's garden declined by 29%.

5 0
4 years ago
In this activity, you'll calculate a probability and use it to predict the result of repeating a simple chance-based trial many
kompoz [17]
1) The outcomes for rolling two dice, the sample space, is as follows:
(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
There are 36 outcomes in the sample space.
2)  The ways to roll an odd sum when rolling two dice are:
(1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3, 2), (3, 4), (3, 6), (4, 1), (4, 3), (4, 5), (5, 2), (5, 4), (5, 6), (6, 1), (6, 3), (6, 5).  There are 18 outcomes in this event.
3)  The probability of rolling an odd sum is 18/36 = 1/2 = 0.5
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