There are 45 numbers out of which 5 numbers are required to win an enormous sum of money
No of ways in which 5 numbers can be selected out of 45 numbers.

out of which there is only combination foe contest winning

When 100 different tickets are bought then
Probability of winning: 
Probably of winning≈0,000082
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P.S. Hello from Russia :^)
Hi.
102+6(7)+8 (your equation)
102+ 42+ 8 (since the order is PEMDAS, multiplication has to go first. 6x7=42
144 + 8 (since you go left to right, 102 +42 has to be 1st. Answer= 144)
152 (now the only thing left is 144 + 8, so do that. Answer= 152.)
Since that's the last step, 152 will be your answer.
Hoped I helped and if you need anymore you could always ask me~
-Dawn
8.2is the answer
Step-by-step explanation:
|CB|+8
Answer:
3 Years
Step-by-step explanation:
7000*22% = 1540
4620/1540 = 3
1540 = the yearly interest
so it will take 3 years of $1540 of interest to get $4620.
Normally you would also have to take into account the interest plus the base varible but since it specifically says 7000 it makes it a simple problem.
hope this helped