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Kay [80]
3 years ago
6

Solve the equation. -3(y+5)=15

Mathematics
1 answer:
Margaret [11]3 years ago
5 0

Answer:

y=-10

Step-by-step explanation:

-3(y+5)=15

y+5=15/-3

y+5=-5

y=-5-5

y=-10

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NS SECTION ONE<br>In the number 416.98, which digit has the greatest value ​
Aneli [31]

the 4 because it's in the hundred place value

I THINK THAT"S HOW YOU DO IT, BUT YOU KNOW JUST TRYING TO HELP YOU :)

5 0
3 years ago
The following is a list of five of the world's busiest airports by passenger traffic for Year 1. Name Location # of Passengers (
mel-nik [20]

Answer:

38.3 %

Step-by-step explanation:

The percentage is the number of passengers of the airports in Asia divided by the total number of passengers, multiplied by 100%. Asia's airports are Capital International (China), and Tokyo (Japan), and the number of passengers of them is 74 + 64 = 138 million.

The total amount of passagerns in the five airports are:

89 + 74 + 67 + 66 + 64 = 360 million.

% = (138/360)*100%

% = 38.3 %

8 0
3 years ago
Read 2 more answers
Variables mathematics
nikdorinn [45]

Answer:

We need to flip the symbol at the end of the question.

answer: x<= 6.5

Step-by-step explanation:

Given inequality: 2(x-4)+5<=4(x-4)

Distribute: 2x-8+5<=4x-16

Undo a constant term from left side: 2x-3<= 4x-16

Combining the like terms: 2x-4x<=-16+3

Undo the coefficient term from left: -2x<=-13

Undo the variable term: x<=(13/2)=6.5

Now checking if this is write: Lets take x=6<6.5

Put x=6 in given inequality:

2(6-4)+5<=4(6-4)

2(2)+5<=4(2)

4+5<=8

9<=8 (which is not possible)

so we need to flip the inequality

2(x-4)+5>=4(x-4)

9>8

4 0
3 years ago
A student earned grades of​ B, B,​ A, C, and D. Those courses had these corresponding numbers of credit​ hours: 4,​ 5, 1,​ 5, 4.
antiseptic1488 [7]

Answer:

<h2> 1.69</h2>

Step-by-step explanation:

Let the five courses with their corresponding credit hours be represented as shown;

FST 201 = 4

FST 203 = 5

FST 112 = 1

FST 219 = 5

FST 223 = 4

If a student earned grades of​ B, B,​ A, C, and D respectively in those courses with the following grading system  A =​4, B =​3, C =​2, D =​1, and F =0, before we can get the student GPA, we need to know the total credit point for the five courses.

Credit point for each course = Number of credit hour * point for each grade

FST 201 = 4 * 4 = 16points (A)

FST 203 = 5 * 4 = 20points (A)

FST 112 = 1 * 4  = 4points (A)

FST 219 = 5 * 4 = 20points (A)

FST 223 = 4 * 4 = 16points (A)

Total credit point = 16+20+4+20+16 = 76points

Total credit point gotten by the student is calculated as thus;

FST 201 = 4 * 3 = 12points (B)

FST 203 = 5 * 3 = 15points (B)

FST 112 = 1 * 4  = 4points (A)

FST 219 = 5 * 2 = 10points (C)

FST 223 = 4 * 1 = 4points (D)

Total credit point gotten by the student = 45points.

student's Grade Point Average​ (GPA) = Total credit point/Total credit point gotten by the student = 76/45 = 1.69 (to 2dp)

5 0
4 years ago
Y=-3x +19 <br> slope:<br> x intercept:<br> y intercept:
aalyn [17]

Answer:

X= -3

Y= 19

Step-by-step explanation:

5 0
3 years ago
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