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Anna [14]
3 years ago
7

NS SECTION ONEIn the number 416.98, which digit has the greatest value ​

Mathematics
1 answer:
Aneli [31]3 years ago
5 0

the 4 because it's in the hundred place value

I THINK THAT"S HOW YOU DO IT, BUT YOU KNOW JUST TRYING TO HELP YOU :)

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Does anyone know geometry?
Naily [24]

Answer:

286m²

Step-by-step explanation The formula to find the surface area of a rectangular prism is A = 2wl + 2lh + 2hw, where w is the width, the l is the length, and the h is the height.

8 0
3 years ago
Read 2 more answers
Given a force of 10N and an acceleration of 5m/s? What is the mass?
likoan [24]

Answer:

<h3>2kg = mass</h3>

Step-by-step explanation:

<h3>What is the mass?</h3>

Mass is a body of matter without definite shape.

Use the Newton's second law of motion formula.

Note: \longrightarrow \sf{F=M*A}

<u>Given:</u>

  • Force = 10N
  • Acceleration = 5m/s

First thing you do is divide.

10/5=2

= 2kg (mass)

Therefore, the final answer is 2kg (mass).

I hope this helps, let me know if you have any questions.

To learn more about the mass:

brainly.com/question/7580108

5 0
2 years ago
6p+2+ p - 3 = 8p - 8​
saul85 [17]
6p+p+2-3=8p-8
7p-1=8p-8
1=1p-8
7=1p
p=7
7 0
3 years ago
Let f(x) = 2x; its inverse is f1(x) = log2x. If f(5) = 32, what is f-1(32)?
PtichkaEL [24]

Answer:

?

Step-by-step explanation:

3 0
3 years ago
Suppose that from the past experience a professor knows that the test score of a student taking his final examination is a rando
DENIUS [597]

Answer:

n=13.167^2 =173.369 and if we round up to the nearest integer we got n =174

Step-by-step explanation:

Previous concepts

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Let X the random variable who represents the test score of a student taking his final examination. We know from the problem that the distribution for the random variable X is given by:

X\sim N(\mu =73,\sigma =10.5)

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Solution to the problem

We want to find the value of n that satisfy this condition:

P(71.5 < \bar X

And we can use the z score formula given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we have this:

P(\frac{71.5-73}{\frac{10.5}{\sqrt{n}}} < Z

And we can express this like this:

P(-0.14286 \sqrt{n} < Z< 0.14286 \sqrt{n} )=0.94

And by properties of the normal distribution we can express this like this:

P(-0.14286 \sqrt{n} < Z< 0.14286 \sqrt{n} )=1-2P(Z

If we solve for P(Z we got:

P(Z

Now we can find a quantile on the normal standard distribution that accumulates 0.03 of the area on the left tail and this value is: z=-1.881

And using this we have this equality:

-1.881 = -0.14286 \sqrt{n}

If we solve for \sqrt{n} we got:

\sqrt{n} = \frac{-1.881}{-0.14286}=13.167

And then n=13.167^2 =173.369 and if we round up to the nearest integer we got n =174

6 0
3 years ago
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